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vaieri [72.5K]
3 years ago
12

a dog walks 14 meters to the east and than 20 meters back to the west for the motion what is the distance moved

Physics
2 answers:
Mariana [72]3 years ago
8 0
The dog moved 6 meters west and 34 meters total
kkurt [141]3 years ago
7 0

Answer:

Distance, d = 34 meters

Explanation:

It is given that,

Distance traveled by a dog towards east is 14 meters and 20 meters back to the west. The overall length of the path covered by an object is called its distance moved. We know that the distance covered by an object is always positive.

d=d_1+d_2

d=14\ m+20\ m

d = 34 meters

So, the distance moved by the dog is 354 meters. Hence, this is the required solution.

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What are 20 examples of energy transformation?
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8 0
3 years ago
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N76 [4]

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Explanation:

8 0
4 years ago
Read 2 more answers
Calculate the percentage increase in length of a wire of diameter 2.2 mm stretched by a load of
vesna_86 [32]

Answer:

0.21%

Explanation:

We are given;

Mass; m = 100 kg

Diameter; d = 2.2 mm = 2.2 × 10^(-3) m

Young's modulus; E = 12.5 x 10^(10) N/m².

Formula for area is;

A = πd²/4

A = (π/4) x (2.2 x 10^(-3))²

A = 3.8 x 10^(-6) m²

Force; F = mg

g is acceleration due to gravity and has a constant value of 9.8 m/s²

F = 100 × 9.8

F = 980 N

Formula for young's modulus is;

E = Stress/strain

Formula for stress = F/A

Formula for strain = ΔL/L

Thus;

E = (F/A)/(ΔL/L)

Making ΔL/L the subject, we have;

ΔL/L = (F/A)/E

Plugging in the relevant values;

ΔL/L = 980/(3.8 x 10^(-6) × 12.5 × 10^(10))

ΔL/L = 0.0021

Then percentage increase in length of a wire = 0.0021 × 100% = 0.21%

8 0
3 years ago
The weight of a block on the inclined plane is 500 N and the angle of incline is 30 degrees. What is the magnitude of the force
yanalaym [24]

Answer:

250 N

433 N

Explanation:

N = Normal force by the surface of the inclined plane

W = Weight of the block = 500 N

f = static frictional force acting on the block

Parallel to incline, force equation is given as

f = W Sin30

f = (500) Sin30

f = 250 N

Perpendicular to incline force equation is given  

N = W Cos30

N = (500) Cos30

N = 433 N

3 0
3 years ago
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