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jek_recluse [69]
3 years ago
11

It takes a crane 59s to lift a flagstone using 342 W of power. How much work is done on the flagstone? ​

Physics
1 answer:
zepelin [54]3 years ago
5 0

Answer: The work done on the flagstone is 20178 J

Explanation:

Power is the rate at which work is done . It is equal to the amount of work done divided by the time it takes to do the work.

Work=Power\times time

Given : work = ?

Power = 342 W = 342J/s

Time = 59 s

Work=342J/s\times 59s=20178J

Thus the work done on the flagstone is 20178 J

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How is p-n-p transistor biased to operate in the active mode​
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Answer:

Shown from explanation.henc2 we

Explanation:

For the transistor to work in the active mode meaning for it to conduct normally, the p- side has to the connected to the positive side of the battery and the n- side the negative terminal of the battery.

Hence we have two batteries such that both ends are connected to the positive terminal and the negative side connected to the middle the n- side of the transistor.

5 0
4 years ago
Would it be true that if you double the distance of an astronaut from a planet, the gravitational pull between them would be hal
velikii [3]

Answer:

Yes

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This is a general physical law derived from

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when distance is doubled the gravitational force will be reduced by quarter not half.

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Calculate the wavelength of the electromagnetic radiation whose frequency is 7.5 x 10^12 Hz
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4 0
4 years ago
A solid non-conducting sphere of radius R carries a charge Q1 distributed uniformly. The sphere is surrounded by a concentric sp
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Answer:

E = k Q₁ / r²

Explanation:

For this exercise that asks us for the electric field between the sphere and the spherical shell, we can use Gauss's law

           Ф = ∫ E .dA = q_{int} / ε₀

where Ф the electric flow, qint is the charge inside the surface

To solve these problems we must create a Gaussian surface that takes advantage of the symmetry of the problem, in this almost our surface is a sphere of radius r, that this is the sphere of and the shell, bone

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for this surface the electric field lines are radial and the radius of the sphere are also, therefore the two are parallel, which reduces the scalar product to the algebraic product.

         E A = q_{int} /ε₀

The charge inside the surface is Q₁, since the other charge Q₂ is outside the Gaussian surface, therefore it does not contribute to the electric field

          q_{int} = Q₁

The surface area is

          A = 4π r²

we substitute

          E 4π r² = Q₁ /ε₀

          E = 1 / 4πε₀ Q₁ / r²

          k = 1/4πε₀

 

          E = k Q₁ / r²

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Find the speed for Barkely, the dog, if he runs 5.5 miles in 3 hours
amm1812

Answer: B

Explanation:

5.5/3

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