Answer:
Shown from explanation.henc2 we
Explanation:
For the transistor to work in the active mode meaning for it to conduct normally, the p- side has to the connected to the positive side of the battery and the n- side the negative terminal of the battery.
Hence we have two batteries such that both ends are connected to the positive terminal and the negative side connected to the middle the n- side of the transistor.
Answer:
Yes
Explanation:
Newton's law of universal gravitation is usually stated that every particle attracts every other particle in the universe with a force which is directly proportional to the product of their masses(m1 and m2) and inversely proportional to the square of the distance between their centers(r).
F = Gm1m2/r²
This is a general physical law derived from
empirical observations by what Isaac Newton called inductive reasoning.
when distance is doubled the gravitational force will be reduced by quarter not half.
velocity of electromagnetic waves=3.0×10^8.
wavelength=velocity/frequency
(3.0×10^8)/(7.5×10^12)
=0.00004
Answer:
E = k Q₁ / r²
Explanation:
For this exercise that asks us for the electric field between the sphere and the spherical shell, we can use Gauss's law
Ф = ∫ E .dA =
/ ε₀
where Ф the electric flow, qint is the charge inside the surface
To solve these problems we must create a Gaussian surface that takes advantage of the symmetry of the problem, in this almost our surface is a sphere of radius r, that this is the sphere of and the shell, bone
R <r <R_a
for this surface the electric field lines are radial and the radius of the sphere are also, therefore the two are parallel, which reduces the scalar product to the algebraic product.
E A = q_{int} /ε₀
The charge inside the surface is Q₁, since the other charge Q₂ is outside the Gaussian surface, therefore it does not contribute to the electric field
q_{int} = Q₁
The surface area is
A = 4π r²
we substitute
E 4π r² = Q₁ /ε₀
E = 1 / 4πε₀ Q₁ / r²
k = 1/4πε₀
E = k Q₁ / r²