Answer: 1
Explanation:
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A. Move 2 m east and then 12 m east; displacement is 14 m east and the distance is 14 m
B. Move 10 m east and then 12 m west, the displacement is 2 m west and the distance is 22 m.
C. Move 8 m west and then 16 m east; the displacement is 8 m east and the distance is 24 m
D. Move 12 m west and then 8 m east; the displacement is 4 m and the distance is 20 m
The formula is
Velocity=frequency×lambda:
Therefore: 4=20×lambda
0.2=lambda
A component of an object moving at a certain velocity can be split into its x and y components (sometimes there is a z component too, but in the case of a question like this, we can imagine the plane the helicopter is travelling in to be 2 dimensions).
Therefore, we can draw a triangle - the hypotenuse having length 86 and being 35 degrees from the ground.
Since the angle ACB (assuming A to be bottom left and B to be top) is a right angle, we can now work with trigonometry:
Sinx = opp/hyp and Cosx = adj/hyp which will give us the components of the vector. Substituting the known values into the equations and rearranging:
86Sin(35) = Opp = 49.3km/h
86Cos(35) = Adj = 70.4km/h
Therefore, the horizontal component (Ax) is 70km/h and the vertical component (Ay) is 49km/h
Answer:
633 nm
Explanation:
E = Energy difference = 1.96 eV
c = Speed of light = 3×10⁸ m/s
h = Planck's constant = 6.626×10⁻³⁴ J/s
Converting eV to J
1 eV = 1.6×10⁻¹⁹ J
1.96 eV = 1.96×1.6×10⁻¹⁹ Joule = 3.136×10⁻¹⁹ Joule
Photon energy equation
∴ Wavelength of light emitted by this laser is 633 nm