Answer:
(a) 315°
(b) 3°
(c) 238°
Step-by-step explanation:
Bearings are measured clockwise from north. The triangle described is illustrated in the attachment.
<h3>(a)</h3>
The bearing of P from R is 180° different from the bearing of R from P it will be ...
135° +180° = 315° . . . . bearing of P from R
__
<h3>(b)</h3>
The bearing of Q from R is 48° more than the bearing of P from R, so is ...
315° +48° = 363°, or 3° . . . . bearing of Q from R
__
<h3>(c)</h3>
The angle QPR has a value that makes the sum of angles in the triangle equal to 180°. It is ...
180° -48° -55° = 77°
The bearing of Q from P is 77° less than the bearing of R from P, so is ...
135° -77° = 58°
As above, the reverse bearing from Q to P is ...
58° +180° = 238° . . . . bearing of P from Q
Answer:
for the first equation
f(-3) = 34
f(4) = 6
for the 2nd equation
f(-3) = -56
f(4) ÷ 70
Step-by-step explanation:
my work is attached in a picture.
all you do is substitute each x value into each equation
1/18 because 1/6 of 1/3 of the girls painted their nail red and 1/6 of 1/3 is 1/6*1/3 or 1/18.
It is 0.45; 0.5; 5/8; 0.75. Hope it helps!