<u>Answer:</u> The value of for the net reaction is 13.94
<u>Explanation:</u>
The given chemical equations follows:
<u>Equation 1:</u>
<u>Equation 2:</u>
The net equation follows:
As, the net reaction is the result of the addition of first equation and the reverse of second equation. So, the equilibrium constant for the net reaction will be the multiplication of first equilibrium constant and the inverse of second equilibrium constant.
The value of equilibrium constant for net reaction is:
We are given:
Putting values in above equation, we get:
Hence, the value of for the net reaction is 13.94
The new volume of the gas that has an initial pressure of 5.6 x 10⁵ Pa is 5.7L. Details about volume of the gas can be found below.
<h3>How to calculate volume?</h3>
The volume of a gas can be calculated using the Boyle's law equation as follows:
P1V1 = P2V2
Where;
- P1 = initial pressure
- P2 = final pressure
- V1 = initial volume
- V2 = final volume
1.53 × 5.6 × 10⁵ = 1.5 × 10⁵ × V2
8.568 × 10⁵ = 1.5 × 10⁵V2
V2 = 8.57 × 10⁵ ÷ 1.5 × 10⁵
V2 = 5.7L
Therefore, the new volume of the gas that has an initial pressure of 5.6 x 10⁵ Pa is 5.7L.
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Carbon:
1s is filled. 2s is filled. 2p is shown to contain two electrons in one orbital and no electrons in the other two orbitals.
<u>Given:</u>
STP (initial) conditions where: P1 = 1 atm and T1 = 298 K
Volume of gas V1 = 310 cm3
Final conditions:
P1 = 2.1 atm
T2 = 2200 + 273 = 2473 K
<u>To determine:</u>
The final volume (V2) occupied by the gas
<u>Explanation:</u>
Using the combined gas law relation:-
P1V1/T1 = P2V2/T2
V2 = (P1V1/T1)(T2/P2)
= (1*310/298)(2473/2.1) = 1225 cm3
Ans: The volume occupied by the gas under uncontrolled explosion is 1225 cm3