Answer:
49.5J/°C
Explanation:
The hot water lost some energy that is gained for cold water and the calorimeter.
The equation is:
Q(Hot water) = Q(Cold water) + Q(Calorimeter)
<em>Where:</em>
Q(Hot water) = S*m*ΔT = 4.184J/g°C*54.56g*(80.4°C-59.4°C) = 4794J
Q(Cold water) = S*m*ΔT = 4.184J/g°C*47.24g*(59.4°C-40°C) = 3834J
That means the heat gained by the calorimeter is
Q(Calorimeter) = 4794J - 3834J = 960J
The calorimeter constant is the heat gained per °C. The change in temperature of the calorimeter is:
59.4°C-40°C = 19.4°C
And calorimeter constant is:
960J/19.4°C =
<h3>49.5J/°C</h3>
<em />
Answer:
5.3 × 10^-4 m or 0.0000053m
Explanation:
Wavelength is given by 2L/m
Where m is the waves bewtween the cavity mirrors which is 100000
L is the cavity length which is 53.00 cm
53/100 (convert to meter) =0.53m
Therefore the wavelength is (2 × 0.53m)/100,000
=0.0000053
= 5.3 × 10^-6 m
We need to use the effusion formula. I have attached a picture of what this formula looks like because it is a bit hard to type.
effusion formula---> Rate 1/ rate 2= √(M2/M1)
as the questions states, hydrogen gas rate is 4 times the rate of the other gas. so, let call gas 1 the unknown and gas 2 the hydrogen
Rate 1= 1
Rate 2= 4
M1=??
M2= 2 grams
now let's plug in the values and solve for the unknown
1/4 = √(2/x)
x= 32 grams
with the choices given, the gases are either O₂, N₂ or O₃.
O₂ is the one whose mass is 32 because oxygen atomic mass in the periodic table is 16 grams. since we have two oxygens, then 16 x 2= 32
the answer is "<span>
32 grams and oxygen "</span>
Answer:
153.6771 amu
Explanation:
From the question given above, the following data were:
Isotope A:
Mass of A = 114.3789 amu
Abundance (A%) = 64.23%
Isotope B:
Mass of B =.?
Abundance (B%) = 100 – A%
Abundance (B%) = 100 – 64.23
Abundance (B%) = 35.77%
average atomic mass of Element Y = 128.4359 amu
The mass of the 2nd isotope (i.e isotope B) can be obtained as follow:
Average atomic mass = [(Mass of A × A%)/100] + [(Mass of B × B%)/100]
128.4359 = [(114.3789 × 64.23)/100] + [(Mass of B × 35.77) /100]
128.4359 = 73.4656 + (Mass of B × 0.3577)
Collect like terms
128.4359 – 73.4656 = Mass of B × 0.3577
54.9703 = Mass of B × 0.3577
Divide both side by 0.3577
Mass of B = 54.9703 / 0.3577
Mass of B = 153.6771 amu
Therefore, the mass of the 2nd isotope is 153.6771 amu
Explanation:
The given reaction is as follows.
Here, [E] = triose phosphate isomerase = 0.1
[S] = Dihydroxy acetone phosphate = 5
[P] = Glyceraldehyde-3-phosphate = 2
Therefore, velocity of the reaction will be as follows.
v = =
where, = Michaelic menten constant =
v =
=
or, = 30 nm/s
Hence, we can conclude that the actual velocity of the forward reaction under physiologic conditions if KM = 10 μM is 30 nm/s.