What is the mass in 6.34x10^23 molecules of calcium chloride

Chemistry

1 answer:

Liono4ka [1.6K]3 years ago

6 0

Answer : The mass of calcium chloride is, 116.84 grams

Solution : Given,

Molar mass of calcium chloride, $CaCl_2$ = 110.98 g/mole

Number of molecules of calcium chloride = $6.34\times 10^{23}$

As we know that,

1 mole of calcium chloride contains $6.022\times 10^{23}$ molecules of calcium chloride

or,

1 mole of calcium chloride contains 110.98 grams of calcium chloride

Or, we can say that

As, $6.022\times 10^{23}$ molecules of calcium chloride present in 110.98 grams of calcium chloride

So, $6.34\times 10^{23}$ molecules of calcium chloride present in $\frac{6.34\times 10^{23}}{6.022\times 10^{23}}\times 110.98=116.84grams$ of calcium chloride

Therefore, the mass of calcium chloride is, 116.84 grams

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