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Karo-lina-s [1.5K]
3 years ago
12

What is the mass in 6.34x10^23 molecules of calcium chloride

Chemistry
1 answer:
Liono4ka [1.6K]3 years ago
6 0

Answer : The mass of calcium chloride is, 116.84 grams

Solution : Given,

Molar mass of calcium chloride, CaCl_2 = 110.98 g/mole

Number of molecules of calcium chloride = 6.34\times 10^{23}

As we know that,

1 mole of calcium chloride contains 6.022\times 10^{23} molecules of calcium chloride

or,

1 mole of calcium chloride contains 110.98 grams of calcium chloride

Or, we can say that

As, 6.022\times 10^{23} molecules of calcium chloride present in 110.98 grams of calcium chloride

So, 6.34\times 10^{23} molecules of calcium chloride present in \frac{6.34\times 10^{23}}{6.022\times 10^{23}}\times 110.98=116.84grams of calcium chloride

Therefore, the mass of calcium chloride is, 116.84 grams

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Scientists should control most possible variables in experiments to get the most valid and correct data. If many variables are included in experiments it is more difficult to interpret what is causing a different outcome.
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3 years ago
Consider the titration of 10.00 mL of a monoprotic weak acid with 0.1234 M NaOH. If the equivalence point volume of NaOH was det
gogolik [260]

The initial concentration of the unknown acid is 0.1900 M.

Explanation:

Titration is a chemical method of analysis to know the concentration and volume of the unknown chemical or analyte.

The formula for the titration is:

Macid x Vacid = Mbase x V base

The volume must be in litres. The volume is given in ml it should be divided with 1000 to obtain values in litre.

Data given are:

volume of acid= 10 ml 0.01 L

Molarity of the acid = ?

volume of the NaOH or base = 15.4 ml or 0.0154 L (equivalence point of the base)

molarity of the base = 0.1234 M

Applying the formula and putting the values, we get

Macid x 0.01 = 0.1234 x 0.0154

Macid =  0.1900 M

The weak acid is having molarity of 0.1900 M against the strong base with molarity of 0.1234M.

4 0
3 years ago
Select the correct answer.
Elina [12.6K]

Answer:

CU

Explanation:

Cu is the correct answer if I'm correct

4 0
2 years ago
Milk of magnesia, a suspension of mg(oh)2 in water, reacts with stomach acid (hcl) in a neutralization reaction. mg(oh)2(s) + 2
defon
Balanced equation for the above reaction is as follows;
Mg(OH)₂ + 2HCl ---> MgCl₂ + 2H₂O
stoichiometry of Mg(OH)₂ to MgCl₂ is 1:1
mass of Mg(OH)₂ reacted - 1.82 g
number of moles of Mg(OH)₂  - 1.82 g/ 58.3 g/mol = 0.0312 mol
number of Mg(OH)₂  moles reacted - number of MgCl₂ moles formed 
number of MgCl₂ moles formed - 0.0312 mol
mass of MgCl₂ formed - 0.0312 mol x 95.2 g/mol = 2.97 g
mass of MgCl₂ formed - 2.97 g

5 0
3 years ago
YO I NEED HELP!!!! APEX PLEASE
podryga [215]
B is the correct answer for it
8 0
3 years ago
Read 2 more answers
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