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mart [117]
3 years ago
6

Give the % composition for each element found in tin (IV) nitride.

Chemistry
1 answer:
drek231 [11]3 years ago
4 0

32.3699% Tin (Sn)

15.2774% Nitrogen (N)

52.3527% Oxygen (O)

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Sugar when dissolved into water, propose whether the compound forms atoms, molecules or lattices. Justify you answer
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atoms

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Considering that the mantle is 44.8% oxygen and 21.5% silicon by mass, calculate the mole ratio of oxygen atoms to silicon atoms
horrorfan [7]

The mantle has a mass of around 4.278 X 10 ^2^4 kg that is around 68.4% of earth's mass.

So to calculate moles we need to first find out the mass of oxygen and silicon present in mantle. It is given that oxygen is 44.8% by mass in mantle and 21.5% by mass in mantle, therefore to calculate its mass, we need to use \text{mass percentage }=\frac{\text{mole of solute}}{\text{mass of solution}}\times100

Now, to calculate mass percentage of oxygen

44.8 =\frac{x}{4.278X10^2^4kg}\times100

x= 191.65\times10^2^2kg

Similarly the mass of silicon can be calculated

21.5 =\frac{x}{4.278X10^2^4kg}\times100

x=91.977\times10^2^2kg

Now, the moles of any substance is calculated by

\text{moles}= \frac{\text{given mass}}{\text{molar mass}}

\text{moles of oxygen}= \frac{191.65\times10^2^2kg}{2.6566962\times10^-^2^6kg}

where, mass of oxygen in kilograms is 2.6566962\times10^-^2^6kg

So,\text{moles of oxygen}=72.1384\times10^4^8\text{moles of O}

Similarly \text{moles of silicon}= \frac{91.977\times10^2^2kg}{4.663\times10^-^2^6kg}

\text{moles of silicon}=19.724\times10^4^8\text{moles of Si}

Now, to calculate mole ratio we need to divide every moles to the lowest calculated mole that is the moles of Si and round it off to the nearest whole number.

\text{mole ratio of oxygen}= \frac{72.138\times10^4^8kg}{19.724\times10^4^8kg}

=3.65\approx 4

\text{mole ratio of Silicon}=\frac{19.724\times10^4^8}{19.724\times10^4^8}

=1

\text{Mole ratio of Oxygen : Mole ratio of Silicon} = 4:1


6 0
4 years ago
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The answer should be A:) The energy produced from the splitting of atoms.

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