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AlekseyPX
3 years ago
9

What are Kr and Xe. (elements)?

Chemistry
1 answer:
nasty-shy [4]3 years ago
8 0
The elements are Krypton and Xenon
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If a pea plant is hybrid for height, this means that
mixas84 [53]

Answer:

A

Explanation:

By nature, a hybrid has one dominante allele and one recessive allele

6 0
3 years ago
Balance the following redox equations by the half-reaction method:
frozen [14]

Answer:

a)  Mn^2+ + 2OH- + H2O2 → MnO2 + 2H2O

b) 2Bi(OH)3 + 3SnO2^2-  → 2Bi + 3SnO3^2- + 3H2O

c) Cr2O7^2- + 3C2O4^2- + 14H+ → 2Cr^3+ +7H2O + 6CO2

d) 2ClO3- + 2Cl- + 4H+   → Cl2 + 2H2O +2ClO2

e) 5 BiO3^- + 14 H+ + 2Mn^2+  → 5Bi^3+ + 7H2O + 2MnO4^-

Explanation:

<em>(a) Mn2 + H2O2 → MnO2 + H2O (in basic solution)</em>

Step 1: The half reactions

Oxidation: Mn2+ + 4OH- → MnO2 + 2H2O + 2e-

Reduction: H2O2 + 2e- + 2H2O  →  2H2O + 2OH-

Step 2: Sum of both half reactions

Mn2+ + 4OH- + H2O2  → MnO2 + 2H2O  + 2OH-

Step 3: the netto reaction

Mn^2+ + 2OH- + H2O2 → MnO2 + 2H2O

<em>(b) Bi(OH)3 + SnO2^2-  → SnO3^2- + Bi (in basic solution)</em>

Step 1: The half reactions

Reduction:  Bi(OH)3 + 3e-  → Bi

Oxidation : Sno2^2-  → SnO3^2- +2e-

Step 2: Balance the half reactions

2* (Bi(OH)3 + 3e-  → Bi + 3OH-)

3* (Sno2^2- +2OH-  → SnO3^2- +2e- + H2O)

Step 3: The netto reaction

2Bi(OH)3 + 3SnO2^2-  → 2Bi + 3SnO3^2- + 3H2O

<em>(c) Cr2O7^2- + C2O4^2- → Cr^3+ + CO2 (in acidic solution)</em>

Step 1: The half reactions

Reduction: Cr2O7^2- + 6e-  → 2Cr+

Oxidation : C2O4^2- → 2CO2 + 2e-

Step 2: Balance the half reactions

Cr2O7^2- + 6e-  +14H+  → 2Cr+ +7H2O

3*(C2O4^2- → 2CO2 + 2e-)

Step 3: The netto reaction

Cr2O7^2- + 3C2O4^2- + 14H+ → 2Cr^3+ +7H2O + 6CO2

<em>(d) ClO3^- + Cl^− </em>→<em> Cl^2 + ClO^2 (in acidic solution)</em>

Step 1: The half reactions

Reduction: 2 ClO3^- + 10e- → Cl2

                      ClO3^- + e- → ClO2

 2 Cl- + 2ClO3^- +8e- →2Cl2

Oxidation: 2Cl- → Cl2 + 2e-

                   Cl- → ClO2 + 5e-

Cl- +ClO3^- → 2ClO2 + 4e-

Step 2: Balance the reactions

2Cl- + 2ClO3^- + 8e- + 12H+ → 2Cl2 + 6H2O

2* (Cl- + ClO3^- + H2O → 2ClO2 + 4e- + 2 H+)

Step 3: The netto reaction

2ClO3^- + 2Cl- + 4H+   → Cl2 + 2H2O +2ClO2

<em>(e) Mn^2 + BiO3^− </em>→<em> Bi^3 + MnO^4− (in acidic solution)</em>

Step 1: The half reactions

Reduction: BiO3^- + 2e- → Bi^3+

Oxidation : Mn^2+ → MnO4^- +5e-

Step 2: Balanced the reactions

5* ( BiO3^- + 2e- + 6H+ → Bi^3+ + 3H2O)

2* ( Mn^2+ + 4H2O →MnO4^- + 5e- + 8H+)

Step 3: The netto reaction

5 BiO3^- + 14 H+ + 2Mn^2+  → 5Bi^3+ + 7H2O + 2MnO4^-

6 0
4 years ago
Why nitration of benzene is easier than that of benzene......... And how is phenol converted to TNT
Colt1911 [192]

Answer:

The nitration of phenol is easier than that of benzene because benzene has delocalised pie-electrons which makes it more stable than phenol.

Phenol is converted to Trinitrotoluene by adding zinc dust to remove the hydroxyl group, then reacted with Aluminium oxide followed by haloalkane.

7 0
3 years ago
Water (2150 gg ) is heated until it just begins to boil. If the water absorbs 5.91×105 JJ of heat in the process, what was the i
Serjik [45]

Answer:

Initial temperature of water was 34,3°C

Explanation:

The heat absorbed in the process (Q) can be written as:

Q = mcΔT

Where the heat is 5,91x10⁵J, m is mass of water (2150g), c is specific heat of water (4,184J/g°C). And ΔT is change in temperature (100°C - x). Replacing:

5,91x10⁵J = 2150g×4,184J/g°C×(100°C - x)

5,91x10⁵J = 899560J - 8995,6J/°Cx

-3,0856x10⁵J = - 8995,6J/°Cx

34,3°C = x

Thus, <em>initial temperature of water was 34,3°C</em>

I hope it helps!

3 0
3 years ago
3. Why are fossils so rare?
Travka [436]

Answer:

fossils are rare bc most dead organisms get decayed by environmental change and decomposers,most fossils are parts of bones and mostly found indry areas like deserts

3 0
3 years ago
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