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Travka [436]
3 years ago
12

What do fossil fuels come from?

Chemistry
1 answer:
lyudmila [28]3 years ago
4 0

Answer:

Fossil fuels are found underneath the Earth's surface at varying depths. These fuels - coal, oil, and natural gas - were formed as a result of the remains of dead plants and organic matter being buried and altered over millions of years.

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Which of the following molecules is responsible for transmitting the energy needed by cells
kolbaska11 [484]
Adenosine triphosphate (ATP)
7 0
3 years ago
Read 2 more answers
7. Write the equation for the positron emission of barium-127.
ziro4ka [17]

The reaction is given by

\\ \rm\Rrightarrow {}^{127}_{56}Ba\longrightarrow {}^{0}_{+1}\beta+{}^{127}_{55}Cs

Barium goes underneath beta decay to form Ceaseum

  • Cs is very mellable element
  • It can melt on your hand
8 0
2 years ago
An electron:
Korvikt [17]
It has a negative charge emits energy when it moves to a lower energy orbit from an excited state and it has the same mass as a proton
4 0
3 years ago
How can you distinguish between a solution, colloid, and suspension?
RSB [31]

Answer:

solution is clear solution while colloidal is between the solution and suspension. And in suspension particles are suspended.

Explanation:

In solution light can be passed without any scattering of light from solute particles while suspension is cloudy and having larger particle size than colloids, if suspension stands for a while particles will settle down easily.

In colloids light  will scattered and dispersed by reflecting with large particles.

3 0
3 years ago
Assuming that the experiments performed in the absence of inhibitors were conducted by adding 5 μl of a 2 mg/ml enzyme stock sol
prohojiy [21]

Hey there!:

From the given data ;

Reaction  volume = 1 mL , enzyme content = 10 ug ( 5 ug in 2 mg/mL )

Enzyme mol Wt = 45,000 , therefore [E]t is 10 ug/mL , this need to be express as "M" So:

[E]t in molar  = g/L * mol/g

[E]t  = 0.01 g/L * 1 / 45,000

[E]t = 2.22*10⁻⁷

Vmax = 0.758 umole/min/ per mL

= 758 mmole/L/min

=758000 mole/L/min => 758000 M

Therefore :

Kcat = Vmax/ [E]t

Kcat = 758000 / 2.2*10⁻⁷ M

Kcat = 3.41441 *10¹² / min

Kcat = 3.41441*10¹² / 60 per sec

Kcat = 5.7*10¹⁰ s⁻¹

Hence   kcat of   xyzase is  5.7*10¹⁰ s⁻¹


Hope that helps!



4 0
3 years ago
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