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Aliun [14]
3 years ago
9

The sum of the measures of the interior angles in a convex polygon is 1,260°. How many sides does the polygon have?

Mathematics
2 answers:
Wittaler [7]3 years ago
8 0

Answer:

C

Step-by-step explanation:

The sum of the interior angles of a polygon is

sum = 180° (n - 2) ← n is the number of sides , thus

180 (n - 2) = 1260 ( divide both sides by 180 )

n - 2 = 7 ( add 2 to both sides )

n = 9

krek1111 [17]3 years ago
5 0
C. 9
Step by step explanation
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if f(1) = -5 and f(n) = f(n-1) +7, find the first four terms and the common difference of the sequence
Alex_Xolod [135]

Answer:

- 5, 2, 9, 16 and d = + 7

Step-by-step explanation:

to obtain the first four terms substitute n = 2, 3, 4 into the recursive formula

f(1) = - 5 ← given

f(2) = f(1) + 7 = - 5 + 7 = 2

f(3) = f(2) + 7 = 2 + 7 = 9

f(4) = f(3) + 7 = 9 + 7 = 16

common difference d = 16 - 9 = 9 - 2 = 2 - (- 5) = 7



6 0
3 years ago
Answer yes or no and explain
Katena32 [7]
No to not being able to get both.

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3 0
3 years ago
Read 2 more answers
Can you tern this into a equation
Aleks [24]

Answer:

n + p x 3 = t

Step-by-step explanation:

n= Navita's money

p= Pawan's money

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8 0
3 years ago
Monica paid sales tax of $1.60 when she bought a new bike helmet. If the sales tax rate was 8%, how much did the store charge fo
Lapatulllka [165]
To find the total from the percent part you have, you divide the part by the percentage.
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5 0
3 years ago
It is known that the population variance equals 484. With a .95 probability, the sample size that needs to be taken to estimate
Hitman42 [59]

Answer:

The minimum sample size is n = 75 so that the desired margin of error is 5 or less.                          

Step-by-step explanation:

We are given the following in the question:

Population variance = 484

Standard deviation =

\sigma^2 = 484\\\sigma =\sqrt{484} = 22

Confidence level = 0.95

Significance level = 0.05

Margin of error = 5

Formula:

Margin of error =

E = z\times \dfrac{\sigma}{\sqrt{n}}\\\\n = (\dfrac{z\times \sigma}{E})^2

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

Putting values, we get

E\leq 5\\\\1.96\times \dfrac{22}{\sqrt{n}} \leq 5\\\\\sqrt{n} \geq 1.96\times \dfrac{22}{5}\\\\n \geq (1.96\times \dfrac{22}{5})^2\\\\n \geq 74.373

Thus, the minimum sample size is n = 75 so that the desired margin of error is 5 or less.

3 0
3 years ago
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