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m_a_m_a [10]
3 years ago
8

In a coordinate plane, what is the distance between (4,-8) and (4, -12)?

Mathematics
2 answers:
Marina86 [1]3 years ago
7 0
Since x co-ordinates are constant, answer has to be difference in y co ordinates therefore the answer is 4
svetoff [14.1K]3 years ago
6 0
The distance between the two values is 4. -8 is 4 away from -12, and the value of x stays the same.
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2 years ago
Please help me ASAP!!
choli [55]

Answer:

r = -4

Step-by-step explanation:

If M is the midpoint of DE, that would mean that the distance from M to D and M to E would be the same.

This creates the equation 1-8r=13-5r.

Now it's just simple algebra.

You add 8r to both sides, creating 1=13+3r. Then, you subtract 13 from both sides, getting 3r=-12. Dividing both sides by 3 and solving for r, you get r=-4.

Checking our answer, you see that 1-8(-4)=1-(-32)=1+32=33, and 13-5(-4)=13-(-20)=13+20=33.

8 0
2 years ago
Help with this math question
ZanzabumX [31]
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5 0
3 years ago
Read 2 more answers
Find the quotient. (12x 2 - 13x - 4) ÷ (4x + 1)
user100 [1]

Answer:

3x-4

Step-by-step explanation:

(12x^2-13x-4)\div(4x+1)= \\\\(3x-4)(4x+1)\div (4x+1)= \\\\3x-4

Hope this helps!

8 0
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