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3 years ago

ANSWER PLEASE NEED HELP

Mathematics

1 answer:

e-lub [12.9K]3 years ago

7 0

Answer:

sry man i dont know

Step-by-step explanation:

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GuDViN [60]

Answer:

sorry whats the question

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

How do you find the area of a triangle ?

katovenus [111]

Answer:

to find the Area of a Triangle, you have to multiply the base times the height of the triangle to find the Area.

Step-by-step explanation:

For example..

If the Base ( bottom part of the triangle) was 10 and the height ( the vertical line of the triangle) was 5, you would multiply them together to get 50. So 5o would be the area of the Triangle.

<h2><em>Hope this helps and have a Great day!</em></h2>

8 0

3 years ago

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Given that lines m and n are parallel and m<60, find the measures of the remaining angles m<3=?

grigory [225]

When you have two parallel lines being cut by a transversal, you can use the next statements for the angles:

The measurement of the angles in green is the same (are congruents)

The measurement of the angles in blue is the same (are congruents)

An angle in green is a complementary angle with an angle in blue. (The addition of the two angles has to be 180º)

You know that:

$m\angle2=60º$

As the angle 3 is congruent with angle 2:

$m\angle3=60º$

6 0

1 year ago

Solve for a.

egoroff_w [7]

Answer: $a=\sqrt{\frac{30}{23} }$

Step-by-step explanation:

$23a^2=30$

Divide by 23

$a^2=\frac{30}{23}$

Extract the square root.

$a=\sqrt{\frac{30}{23} }$

3 0

3 years ago

Find the area of the largest square contained by a circle of radius r = 1cm. Explain your answer and justify that it is correct.

Elena-2011 [213]

Answer:

2 square cm

Step-by-step explanation:

Given :

A square is inscribed in a circle whose radius is r = 1 cm

Therefore, the diameter of the circle is 2 r = 2 x 1

= 2 cm.

So the diagonal of the square is 2r.

Using the Pythagoras theorem, we find each of the side of the triangle is $r \sqrt 2$ .

Therefore, the area of the square is given by $\text{(side)}^2$

= $(r\sqrt 2)^2$

$= 2 r^2$

$= 2 (1)^2$

$=2 \ cm^2$

Hence the area of the largest square that is contained by a circle of radius 1 cm is 2 cm square.

7 0

3 years ago