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Alexandra [31]
3 years ago
15

At the end of a race a runner decelerates from a velocity of 8.90 m/s at a rate of 1.70 m/s2. (a) How far in meters does she tra

vel in the next 6.30 s? (Assume the deceleration of 1.70 m/s2 is constant over the full 6.30 s.)
Physics
1 answer:
Ad libitum [116K]3 years ago
7 0

Answer:

x=22.33m

Explanation:

Kinematics equation for constant deceleration:

x =v_{o}*t - 1/2*at^{2}=8.9*6.3-1/2*1.70*6.3^{2}=22.33m

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Answer:

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Explanation:

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a. Quadruped arm and opposite leg raise

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8 0
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Explanation:

Well.. I hope it helps you..

Just correct me if I'm wrong..

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