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LuckyWell [14K]

3 years ago

14

If two charged balloons are 24cm apart and they feel a force of electrical repulsion of 20N, what would the force of electrical

repulsion become if the balloons were moved closer together
to a distance of 4cm?

1 answer:

OverLord2011 [107]3 years ago

5 0

Answer:

Soory

Explanation:

I really dont know but i will send you wait

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A 500. gram sample of nickle-63 has a half-life of 100. years and has decayed for 500. years. How much of the original 500. gram

Snowcat [4.5K]

Halve it five times:
250
125
62.5
31.25
15.6
ta-da

6 0

4 years ago

Read 2 more answers

A Carnot engine has an efficiency of 0.537, and the temperature of its cold reservoir is 379 K.

katen-ka-za [31]

Answer:

(A) Th = 818.6 K

(B) Qh = 14211.7 J

Explanation:

efficiency (n) = 0.537

temperature of cold reservoir (Tc) = 379 K

heat rejected (Qc) = 6580 J

(A) find the temperature of the hot reservoir (Th)

n = 1 - $\frac{Tc}{Th}$

0.537 = 1 - $\frac{379}{Th}$

$\frac{379}{Th}$ = 1 - 0.537 = 0.463

Th = $\frac{379}{0.463}$

Th = 818.6 K

(B) what amount of heat is put into the engine (Qh) ?

from $\frac{Tc}{Th} = \frac{Qc}{Qh}$

Qh = 6580 ÷ $\frac{379}{818.6}$

Qh = 14211.7 J

8 0

3 years ago

At a waterpark, sleds with riders are sent along a slippery, horizontal surface by the release of a large, compressed spring. Th

steposvetlana [31]

The sleds speed when the spring returns toits uncompressed length is v = 0.03 m/s.

<u>Explanation</u>:

Given,

force constant = 42 N/cm = 0.42 N/m, mass m = 68 kg, spring x = 0.39 m

The potential energy, U, stored in the spring is

U = 1/2 kx^2

= 1 / 2 $\times$ 0.42 $\times$ (0.39)^2

= 0.032 J

All its potential energy has been converted into kinetic energy since it has a uncompressed length.

K = 1/2 mv^2

v = sqrt (2K / m)

= √(( 2 $\times$ 0.032) / 68)

v = 0.03 m/s .

4 0

4 years ago

According to the concept of length contraction, what happens to the length of an object as it approaches the speed of light and

lord [1]

When an object moves its length contracts in the direction of motion. The faster it moves the shorter it gets in the direction of motion.
The object in this question moves and then stops moving. So it's length first contracts and then expands to its original length when the motion stops.
The speed doesn't have to be anywhere near the speed of light. When the object moves its length contracts no matter how fast or slow it's moving.

8 0

4 years ago

A copper wire is 1.6 m long and its diameter is 1.1 mm. If the wire hangs vertically, how much weight (in N) must be added to it

qaws [65]

Answer:

Weight required = 194.51 N

Explanation:

The elongation is given by

$\Delta L=\frac{PL}{AE}$

Length , L= 1.6 m

Diameter, d = 1.1 mm

Area

$A=\frac{\pi d^2}{4}=\frac{\pi \times (1.1\times 10^{-3})^2}{4}=9.50\times 10^{-7}m^2$

Change in length, ΔL = 2.8 mm = 0.0028 m

Young's modulus of copper, E = 117 GPa = 117 x 10⁹ Pa

Substituting,

$\Delta L=\frac{PL}{AE}\\\\0.0028=\frac{P\times 1.6}{9.50\times 10^{-7}\times 117\times 10^9}\\\\P=194.51N$

Weight required = 194.51 N

8 0

3 years ago