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3 years ago

13

The Celsius tempersture scale is based on which of the following? a) vapor b) the human body c) the boiling point of air d) the

boiling and freezing points of water

2 answers:

Darina [25.2K]3 years ago

8 0

I think d is the correct answer

tatuchka [14]3 years ago

8 0

I believe the answer is D because the freezing point for water is 0, and the boiling point is 100 in the Celsius scale, so D makes the most sense

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M84, M87, and NGC 4258 all have accretion disks around their central black holes for which the rotational velocities have been m

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Answer:

<u>For M84:</u>

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<u>For M87:</u>

M = 2307.46 * 10³⁶ kg

Explanation:

1 parsec, pc = 3.08 * 10¹⁶ m

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$M = \frac{v^{2} r}{G}$ .............(1)

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r = 8 pc = 8 * 3.08 * 10¹⁶

r = 24.64 * 10¹⁶ m

v = 400 km/s = 4 * 10⁵ m/s

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Substituting these values into equation (1)

$M = \frac{( 4*10^{5}) ^{2} *24.64* 10^{16} }{6.674 * 10^{-11} }$

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<u>For M87:</u>

r = 20 pc = 20 * 3.08 * 10¹⁶

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Answer:

(a). The speed of the first ball after the collision is 1.95 m/s.

(b). The direction of the first ball after the collision is 44.16° due south of east.

Explanation:

Given that,

Velocity of one ball u₁= 2.2i m/s

Velocity of second ball u₂=- 0.80i m/s

Final velocity of the second ball v₂= 1.36j m/s

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$m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}$

Along X- axis

$m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}$

$v_{1}=u_{1}+u_{2}$

Put the value into the formula

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$v_{1}=-v_{2}$

Put the value into the formula

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$v_{1}=\sqrt{(1.4)^2+(1.36)^2}$

$v_{1}=1.95\ m/s$

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Using formula of direction

$\tan\theta=\dfrac{v_{2}}{v_{1}}$

$\tan\theta=\dfrac{-1.36}{1.4}$

$\theta=\tan^{-1}\dfrac{-1.36}{1.4}$

$\theta=-44.16^{\circ}$

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