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2 years ago

13

The Celsius tempersture scale is based on which of the following? a) vapor b) the human body c) the boiling point of air d) the

boiling and freezing points of water

2 answers:

Darina [25.2K]2 years ago

8 0

I think d is the correct answer

tatuchka [14]2 years ago

8 0

I believe the answer is D because the freezing point for water is 0, and the boiling point is 100 in the Celsius scale, so D makes the most sense

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A 65kg has the weight force of

AURORKA [14]

Answer:

65*9.8=637N

Explanation:

8 0

2 years ago

A woman who weighs 500 N stands on an 8.0-m-long board that weighs 100 N. The board is supported at each end. The support force

aniked [119]

Answer:

The woman's distance from the right end is 1.6m = (8-6.4)m.

The principles of moments about a point or axis running through a point and summation of forces have been used to calculate the required variable.

Principle of moments: the sun of clockwise moments must be equal to the sun of anticlockwise moments.

Also the sun of upward forces must be equal to the sun of downward forces.

Theses are the conditions for static equilibrium.

Explanation:

The step by step solution can be found in the attachment below.

Thank you for reading this solution and I hope it is helpful to you.

8 0

3 years ago

Can someone help? I’ll give brainlest .

MrRissso [65]

Answer:

I think it’s 6.8 m/s2

Explanation:

Please give me brainlist if the answer is right.

5 0

3 years ago

Read 2 more answers

A war wolf is a device used during the middle ages to assault fortifications with large rocks. A simple trebuchet is constructed

Katarina [22]

Answer:v=41.23 m/s

Explanation:

Given

mass of heavy object $m_1=52 kg$

distance of $m_1$ from the axle $r_1=14 cm$

mass of rock $m_2=123 gm$

Length of rod $=4.1 m$

distance of $m_2$ from axle $r_2=4.1-0.14=3.96 m$

Net torque acting is

$T_{net}=m_1gr_1-m_2gr_2$

$T_{net}=52\times 0.14\times g-0.123\times 3.96\times g$

$T_{net}=6.793\times 9.8$

$T_{net}=66.57 N-m$

Work done by $T_{net}$ is converted to rock kinetic Energy

thus

$T_{net}\times \theta =\frac{mv^2}{2}$

Where $\theta =angle\ turned =\frac{\pi }{2}$

$v= velocity\ at\ launch$

$66.57\times \frac{\pi }{2}=\frac{0.123\times v^2}{2}$

$v^2=66.57\times \pi$

$v=\sqrt{1700.511}$

$v=41.23 m/s$

3 0

3 years ago

Thomas needs to move an 80 kg rock, but cannot lift it. He decides to use a

ArbitrLikvidat [17]

Answer:

4

Explanation:

The weight of the rock is W = mg = (80 kg) (10 m/s²) = 800 N.

The mechanical advantage is therefore 800 N / 200 N = 4.

5 0

2 years ago