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kykrilka [37]
3 years ago
8

When radio waves try to pass through a city, they encounter thin vertical slits: the separations between the buildings. This cau

ses the radio waves to diffract. In this problem, you will see how different wavelengths diffract as they pass through a city and relate this to reception for radios and cell phones. You will use the angle from the center of the central intensity maximum to the first intensity minimum as a measure of the width of the central maximum (where nearly all of the diffracted energy is found).
Physics
1 answer:
Westkost [7]3 years ago
4 0

Answer:

\theta= sin^{-1}(\frac{\lambda}{a})

Explanation:

Assuming we have to find

Find the angle theta to the first minimum from the center of the central maximum (Expressing answer in terms of λ  and a.):

a= avg separation between the building.

λ = wavelength

for single slit diffraction we have

a sinθ =nλ

for the first minimum n=1

a sinθ =λ

therefore,

\theta= sin^{-1}(\frac{\lambda}{a})

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Lorico [155]

Answer:r_2=11.81 cm

Explanation:

Given

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potential Energy due to Magnetic Field =Kinetic Energy of Particle

qV=\frac{mv^2}{2}

v=\sqrt{\frac{2qV}{m}}

and we know

Force due to magnetic field will Provide centripetal Force

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B=\frac{\sqrt{\frac{2Vm}{q}}}{r}

and B is equal for both particles

thus \frac{m}{r^2}=constant

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4 0
3 years ago
An object has a mass of 6kg. calculate it's gpe​
m_a_m_a [10]

Explanation:

When m=<em>mass</em>

G=<em>a</em><em>c</em><em>c</em><em>e</em><em>l</em><em>e</em><em>r</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>d</em><em>u</em><em>e</em><em> </em><em>t</em><em>o</em><em> </em><em>gravity</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>H</em><em>=</em><em>h</em><em>e</em><em>i</em><em>g</em><em>h</em><em>t</em>

<em>U</em><em>s</em><em>i</em><em>n</em><em>g</em><em> </em><em>f</em><em>o</em><em>r</em><em>m</em><em>u</em><em>l</em><em>a</em>

<em>M</em><em>g</em><em>h</em>

<em>(</em><em>M</em><em>=</em><em>6</em><em>, </em><em>g</em><em>=</em><em>10</em><em>,</em><em>h</em><em>=</em><em>?</em><em>) </em>

6×10×h

=60joules

7 0
3 years ago
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