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kykrilka [37]
3 years ago
8

When radio waves try to pass through a city, they encounter thin vertical slits: the separations between the buildings. This cau

ses the radio waves to diffract. In this problem, you will see how different wavelengths diffract as they pass through a city and relate this to reception for radios and cell phones. You will use the angle from the center of the central intensity maximum to the first intensity minimum as a measure of the width of the central maximum (where nearly all of the diffracted energy is found).
Physics
1 answer:
Westkost [7]3 years ago
4 0

Answer:

\theta= sin^{-1}(\frac{\lambda}{a})

Explanation:

Assuming we have to find

Find the angle theta to the first minimum from the center of the central maximum (Expressing answer in terms of λ  and a.):

a= avg separation between the building.

λ = wavelength

for single slit diffraction we have

a sinθ =nλ

for the first minimum n=1

a sinθ =λ

therefore,

\theta= sin^{-1}(\frac{\lambda}{a})

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Answer:

KE2/KE1=0.71

Explanation:

By conservation of the linear momentum:

m1*V1 = (m1+m2)*V2

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