So, 3 liters of water, add 1/2 liter of lemonade, that's 3 and 1/2 liters of lemonade.
so in short, how many times does 1/3 go into 3 and 1/2?
let's change the mixed to "improper" and divide then.
Answer:
<A = 16.82 degrees
Step-by-step explanation:
Tan^-1 = opposite/adjacent
Tan^-1 (13/43) = 16.82 degrees
Answer:
M=9
EXPLANATION:
Let R represent Ronald’s present age. Let M represent Miley’s present age. Three years from now, Ronald and Miley will be R+3 and M+3 years old, respectively.
Your assertion “Three years from now, Ron’s age will be 2 times that of Miley's” can be written as
R + 3 = 2*(M + 3)
Similarly, your assertion “Three years ago, Ron's age was 3 times that of Miley's” can be written as
R - 3 = 3*(M-3)
We can add the left side of these equations together, and also the right side of these equations together, and obtain a new equation …
R + 3 + R - 3 = 2*(M + 3) + 3*(M - 3) = 2M + 6 + 3M - 9 = 5M - 3
This can be simplified to
2R = 5M - 3
We can divide both sides of the last equation by 2, and obtain ..
(2/2) * R = (5/2) * M - 3/2, or R = (5/2) * M - 3/2.
Now we can “plug in” the last equation into either of our first two equations of this post, and solve for M.
Using the first equation, we have
(5/2) * M - 3/2 + 3 = 2 *(M + 3) = 2M + 6
We now have
(5/2) * M + 3/2 = 2M + 6
The left side of this equation can be rewritten as
(5M + 3) / 2, so we obtain
(5M + 3) / 2 = 2M + 6
Multiplying both sides by 2, we have
5M + 3 = 4M + 12
Subtracting 4M and 3 from both sides, we obtain
M = 9
Miley’s present age is 9.
plss give brainliest
If I understand the question, you have to get n alone. in this case, you have to subtract 7 from both sides, resulting in n (is less than) -10
Hello,
Very nice as problem.
2 solutions:
1 quater,8 dimes, 2 pennies
and
3 quaters,3 dimes, 2 pennies
since
107=( 0, 0, 107) but : 100= 0*25+ 0*10+ 100
107=( 0, 1, 97) but : 100= 0*25+ 1*10+ 90
107=( 0, 2, 87) but : 100= 0*25+ 2*10+ 80
107=( 0, 3, 77) but : 100= 0*25+ 3*10+ 70
107=( 0, 4, 67) but : 100= 0*25+ 4*10+ 60
107=( 0, 5, 57) but : 100= 0*25+ 5*10+ 50
107=( 0, 6, 47) but : 100= 0*25+ 6*10+ 40
107=( 0, 7, 37) but : 100= 0*25+ 7*10+ 30
107=( 0, 8, 27) but : 100= 0*25+ 8*10+ 20
107=( 0, 9, 17) but : 100= 0*25+ 9*10+ 10
107=( 0, 10, 7) but : 100= 0*25+ 10*10+ 0
107=( 1, 0, 82) but : 100= 1*25+ 0*10+ 75
107=( 1, 1, 72) but : 100= 1*25+ 1*10+ 65
107=( 1, 2, 62) but : 100= 1*25+ 2*10+ 55
107=( 1, 3, 52) but : 100= 1*25+ 3*10+ 45
107=( 1, 4, 42) but : 100= 1*25+ 4*10+ 35
107=( 1, 5, 32) but : 100= 1*25+ 5*10+ 25
107=( 1, 6, 22) but : 100= 1*25+ 6*10+ 15
107=( 1, 7, 12) but : 100= 1*25+ 7*10+ 5
107=( 1, 8, 2) is good
107=( 2, 0, 57) but : 100= 2*25+ 0*10+ 50
107=( 2, 1, 47) but : 100= 2*25+ 1*10+ 40
107=( 2, 2, 37) but : 100= 2*25+ 2*10+ 30
107=( 2, 3, 27) but : 100= 2*25+ 3*10+ 20
107=( 2, 4, 17) but : 100= 2*25+ 4*10+ 10
107=( 2, 5, 7) but : 100= 2*25+ 5*10+ 0
107=( 3, 0, 32) but : 100= 3*25+ 0*10+ 25
107=( 3, 1, 22) but : 100= 3*25+ 1*10+ 15
107=( 3, 2, 12) but : 100= 3*25+ 2*10+ 5
107=( 3, 3, 2) is good
107=( 4, 0, 7) but : 100= 4*25+ 0*10+ 0
