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3 years ago

The mass of one atom would best be measured in this unit:

Chemistry

2 answers:

UkoKoshka [18]3 years ago

8 0

Umm i think answer B.gram

guapka [62]3 years ago

8 0

A. is your answer.

plz mark me as brainliest. i really need it ;-;.

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Reagent needed to convert sulphur dioxide to Sulphur

Harman [31]

<span>6 + x = 12. To evaluate an algebraic expression, you have to substitute a number for each variable and perform the arithmetic operations. In the example above, the variable x is equal to 6 since 6 + 6 = 12. If we know the value of our variables, we can replace the variables with their values and then evaluate the expression.</span>

5 0

3 years ago

According to Archimedes' principle, the mass of a floating object equals the mass of the fluid displaced by the object. A 150-lb

julsineya [31]

Answer:

The density of the swimmer is 0.0342 lbm/in3.

This value makes sense as the density of the body is very similar to the water.

Explanation:

If the swimmers is floating, the weight of the swimmer must be equal to the upward buoyant force.

We can express the weight force as the product of density and volume of the swimmer.

Then

$\rho_{swimmer}*V_{swimmer}=\rho_{water}*V_{water_displaced}\\\\\rho_{swimmer}*V_{swimmer}=\rho_{water}*0.95**V_{swimmer}\\\\\rho_{swimmer}=0.95*\rho_{water}\\\\\rho_{swimmer}=0.95*0.036 lbm/in3\\\\\rho_{swimmer}=0.0342lbm/in3$

It makes sense as the density of the body is very similar to the water.

5 0

2 years ago

Does anyone know what order?

mamaluj [8]

I believe it is decomposition, neutralization, combustion

4 0

2 years ago

Read 2 more answers

The equilibrium constant for the reaction

FinnZ [79.3K]

Answer: The concentrations of $Cl_2$ at equilibrium is 0.023 M

Explanation:

Moles of $Cl_2$ = $\frac{\text {given mass}}{\text {Molar mass}}=\frac{10g}{71g/mol}=0.14mol$

Volume of solution = 1 L

Initial concentration of $Cl_2$ = $\frac{0.14mol}{1L}=0.14M$

The given balanced equilibrium reaction is,

$COCl_2(g)\rightleftharpoons CO(g)+Cl_2(g)$

Initial conc. 0.14 M 0 M 0M

At eqm. conc. (0.14-x) M (x) M (x) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[CO]\times [Cl_2]}{[COCl_2]}$

Now put all the given values in this expression, we get :

$4.63\times 10^{-3}=\frac{x)^2}{(0.14-x)}$

By solving the term 'x', we get :

x = 0.023 M

Thus, the concentrations of $Cl_2$ at equilibrium is 0.023 M

7 0

3 years ago

2. How many grams of water can be heated from 20.0 oC to 75oC using 12500.0 Joules?

kenny6666 [7]

Answer;

= 0.054 kg or 54 g

Explanation;

Using the equation; Q = mcΔT where Q is the quantity of heat transferred, m is the mass, c is specific heat of the substance, ΔT is delta T, the change in temperature.

ΔT = 75 - 20 = 55 C.

Solve the equation for m

m = Q/ cΔT

Mass = 12500 / (55 × 4200)

= 0.054 kg or 54 g

4 0

3 years ago

Read 2 more answers