All categories

3 years ago

PLEASE HELPPPPPP! I'll appreciate!

Chemistry

1 answer:

blagie [28]3 years ago

8 0

Answer:

A,Z,H,Y,T

Hope this helpsss!!!!! Best!!!!

You might be interested in

Given that a particular photon has a frequency of 2.2 x 10'7 Hz, calculate the photon's energy. Submit your answer in

BlackZzzverrR [31]

Answer:

E = 15×10⁻²⁹ J

Explanation:

Given data:

Frequency of photon = 2.2× 10⁷ Hz

Energy of photon = ?

Solution:

Formula:

E = h.f

h = 6.63×10⁻³⁴ Js

by putting values,

E = 6.63×10⁻³⁴ Js × 2.2× 10⁷ s⁻¹

E = 14.586 ×10⁻²⁹ J

E = 15×10⁻²⁹ J

The energy of photon is 15×10⁻²⁹ J.

5 0

3 years ago

During an experiment,what is the factor you are testing called

Step2247 [10]

Answer:

the answer is variable

4 0

3 years ago

Hydrogen is 99% hydrogen-1; 0.8% hydrogen-2; and 0.2% hydrogen-3. calculate it's average atomic mass

alexandr402 [8]

Average atomic mass is =1.11 u

need brainliest

4 0

3 years ago

Read 2 more answers

If 17. 6 g of hcl are used to produce a 14. 5 l solution, what is the ph of the solution?.

kati45 [8]

This problem is providing us with the mass of hydrochloric acid and the volume of solution and asks for the pH of the resulting solution, which turns out to be 1.477.

<h3>pH calculations</h3>

In chemistry, one can calculate the pH of a solution by firstly obtaining its molarity as the division of the moles of solute by the liters of solution, so in this case for HCl we have:

$M=\frac{17.6g*\frac{1mol}{36.46g} }{14.5L} \\\\M=0.0333 M$

Next, due to the fact that hydrochloric acid is a strong acid, we realize its concentration is nearly the same to the released hydrogen ions to the solution upon ionization. Thereby, the resulting pH is:

$pH=-log(0.0333)\\\\pH=1.477$

Which conserves as much decimals as significant figures in the molarity.

Learn more about pH calculations: brainly.com/question/1195974

3 0

2 years ago

Pipettes are used when measuring the volumes of liquids with high degree of precision. The following volumes were obtained durin

never [62]

Answer:

0.075

Explanation:

First obtain the mean of the measurement;

Mean = 10.15 + 9.95 + 9.99 + 10.02/4 = 10.03

Then obtain d^2= (mean-score)^2 for each score;

(10.15-10.03)^2 = 0.0144

(9.95-10.03)^2 = 0.0064

(9.99-10.03)^2 = 0.0016

(10.02-10.03)^2= 0.0001

∑d^2= 0.0144 + 0.0064 + 0.0016 + 0.0001

∑d^2= 0.0225

Variance = ∑d^2/N = 0.0225/4 = 0.005625

Standard deviation= √0.005625

Standard deviation= 0.075

6 0

3 years ago