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FromTheMoon [43]
3 years ago
6

A charge +q is located at the origin, while an identical charge islocated on the x axis at x= +0.50 m. A third charge of +2 q is

located on the x axis at such a place that the net electrostaticforce on the charge at the origin doubles, its direction remainingunchanged. Where should the third charge be located.

Physics
1 answer:
stich3 [128]3 years ago
7 0

Answer: 0.71m

Explanation:

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vivado [14]

Answer:

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Explanation:

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4 years ago
A variable that is described using both a number and direction is called
gizmo_the_mogwai [7]

they are called a vector.

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4 years ago
A uniform charge density of 600 nC/m3 is distributed throughout a spherical volume (radius = 14 cm). Consider a cubical (3.2 cm
jolli1 [7]

Answer: The electric flux through this surface is 2.22 Nm^2/C

Explanation: Please see the attachments below

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3 years ago
The object moves with BLANK from A to B. it BLANK from B to C. it moves with BLANK from C to D.
Ganezh [65]

Note that this is a position vs time graph.

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4 0
3 years ago
If the mass of a planet is 0.231 mE and its radius is 0.528 rE, estimate the gravitational field g at the surface of the planet.
crimeas [40]

Answer:

8.1 m/s^2

Explanation:

The strength of the gravitational field at the surface of a planet is given by

g=\frac{GM}{R^2} (1)

where

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M is the mass of the planet

R is the radius of the planet

For the Earth:

g_E = \frac{GM_E}{R_E^2}=9.8 m/s^2

For the unknown planet,

M_X = 0.231 M_E\\R_X = 0.528 R_E

Substituting into the eq.(1), we find the gravitational acceleration of planet X relative to that of the Earth:

g_X = \frac{GM_X}{R_X^2}=\frac{G(0.231M_E)}{(0.528R_E)^2}=\frac{0.231}{0.528^2}(\frac{GM_E}{R_E^2})=0.829 g_E

And substituting g = 9.8 m/s^2,

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3 0
3 years ago
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