Ask question

Ask question

All categories

love history [14]

3 years ago

6

A. B. C. D. Please help

2 answers:

MA_775_DIABLO [31]3 years ago

8 0

Answer:

The answer is A, B, C and D

Explanation:

(is that how it works?)

marissa [1.9K]3 years ago

4 0

Answer:

B

Explanation:

From the question above, you can see in the picture, the first,second ,third models have respectively 4 e in second circle (Carbon), 5 e in second circle(Nitrogen) , 6e in second circle(Oxygen) . So, to maintain the serial, the next model must have 7 e in second circle of the atom which is option B : Fluorine

You might be interested in

A circular wooden loop of mass m and radius R rest on a flat horizontal friction less surface. A bullet, also of mass m, and mov

bearhunter [10]

Answer:

w = vR/3

Explanation:

The centre of mass of the loop to bullet system is given by D / 4 from centre of loop, which is equivalent to R / 2 from its centre.

From the principle of conservation of linear momentum , we have

m*v = 2*m* Vcm

Where v = velocity of bullet, Vcm = velocity of wood

Hence, we have

Vcm = v2

Also, from the conservation of angular momentum about the centre of mass.

M*V*(R/2) = Ic*w - equation (I)

where Ic = moment of inertia and w = angular velocity

Ic for a ring is given by $mr^2 + m(r/2)^2$

Ic of a bullet is given by $m(r/2)^2$

Hence, the moment of inertia of the system is given by the summation of the two moments of inertia Ic(ring) + Ic(bullet) which gives

Ic(system) = $3*m*R^2/2$

Substituting back into equation (I), we have

$m*v*R^2=3*m*R^2*w/2$

Hence, we obtain w =vR/3

w=v3R

4 0

3 years ago

A ball is launched vertically with an initial speed of y˙0= 50 m/s, and its acceleration is governed by y¨=-g-cDy˙2, where the a

stira [4]

Answer:

Explanation:

Given

acceleration is given by

$a=-g-c_Dv^2$

where $\ddot{y}=a$

$\dot{y}=v$

Also acceleration is given by

$a=v\frac{\mathrm{d} v}{\mathrm{d} s}$

$ds=\frac{v}{a}dv$

$\int ds=\int \frac{v}{-g-0.001v^2}dv$

$\Rightarrow Let -g-0.001v^2=t$

$-0.001\times 2vdv=dt$

$vdv=-\frac{dt}{0.002}$

$at\ v_0=50\ m/s,\ t=-g-0.001(50)^2$

$t=-g-2.5$

at $v=0,\ t=-g$

$\int_{0}^{s}ds=\int_{-g}^{-g-2.5}\frac{-dt}{0.002t}$

$\int_{0}^{s}ds=\int^{-g}_{-g-2.5}\frac{dt}{0.002t}$

$s=\frac{1}{0.002}lnt|_{-g}^{-g-2.5}$

$s=\frac{1}{0.002}\ln (\frac{g+2.5}{g})$

$s=113.608\ m$

when air drag is neglected maximum height reached is

$h=\frac{v_0^2}{2g}$

$h=\frac{50^2}{2\times 9.8}$

$h=127.55\ m$

3 0

3 years ago

3. What is the acceleration of a 10 kg mass pushed by a 5 N force?

insens350 [35]

Answer:

F=ma

Plug it in:

5=10a

5/10=(10a)/10

.5m/s²=a

Explanation:

Brainliest?

5 0

3 years ago

Read 2 more answers

Which statement about cellulose is true?

zlopas [31]

Is there any answers? Or is it asking you to choose?

6 0

3 years ago

Read 2 more answers

Scientists have discovered just over _____ different elements with unique properties.

Y_Kistochka [10]

100. (: hope this helps

8 0

3 years ago

Read 2 more answers