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Bas_tet [7]
3 years ago
14

In an emergency an airplane needs to land on a short runway at Albany County Airport. The plane comes in for a landing with a sp

eed of 95 m/s. The planes maximum magnitude of acceleration is 7.07 m/s2 as it comes to a stop. (a) What is the minimum time interval needed for this plane to stop?
Physics
1 answer:
zvonat [6]3 years ago
6 0

Answer:

t = 13.43 s

Explanation:

In order to find the minimum time required by the plane to stop, we will use the first equation of motion. The first equation of motion is written as follows:

Vf = Vi + at

where,

Vf = Final Velocity of the Plane = 0 m/s (Since, the plane finally stops)

Vi = Initial Velocity of the Plane = 95 m/s

a = deceleration of the plane = - 7.07 m/s²

t = minimum time interval needed to stop the plane = ?

Therefore,

0 m/s = 95 m/s + (- 7.07 m/s²)t

t = (95 m/s)/(7.07 m/s²)

<u>t = 13.43 s</u>

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A river has a steady speed 0.500 m/s. A student swims upstream a distance of1.00 km and swims back to the starting point. a) If
Ivahew [28]

Answer:

a) 33.6 min

b) 13.9 min

c)  Intuitively, it takes longer to complete the trip when there is current because, the swimmer spends much more time swimming at the net low speed (0.7 m/s) than the time he spends swimming at higher net speed (1.7 m/s).


Explanation:


The problem deals with relative velocities.

  • Call Vr the speed of the river, which is equal to 0.500 m/s
  • Call Vs the speed of the student in still water, which is equal to 1.20 m/s
  • You know that when the student swims upstream, Vr and Vs are opposed and the net speed will be Vs - Vr
  • And when the student swims downstream, Vr adds to Vs and the net speed will be Vs + Vr.

Now, you can state the equations for each section:

  • distance = speed × time
  • upstream: distance = (Vs - Vr) × t₁ = 1,000 m
  • downstream: distance = (Vs + Vr) × t₂ = 1,000 m

Part a). To state the time, you substitute the known values of Vr and Vs and clear for the time in each equation:

  • (Vs - Vr) × t₁ = 1,000 m
  • (1.20 m/s - 0.500 m/s) t₁ = 1,000 m⇒ t₁ = 1,000 m / 0.70 m/s ≈ 1429 s
  • (1.20 m/s + 0.500 m/s) t₂ = 1,000 m ⇒ t₂ = 1,000 m / 1.7 m/s ≈ 588 s
  • total time = t₁ + t₂ = 1429s + 588s =  2,017s
  • Convert to minutes: 2,0147 s ₓ 1 min / 60s ≈ 33.6 min

Part b) In this part you assume that the complete trip is made at the velocity Vs = 1.20 m/s


  • time = distance / speed = 1,000 m / 1.20 m/s ≈ 833 s ≈ 13.9 min

Part c) Intuitively, it takes longer to complete the trip when there is current because the swimmer spends more time swimming at the net speed of 0.7 m/s than the time than he spends swimming at the net speed of 1.7 m/s.

6 0
4 years ago
How much work is done when you push a crate horizontally with 150 N across a 13-m floor
Mila [183]
Work = (force) x (distance)

When a force of 150 N pushes through a distance of 13 meters,
it does

             Work = (150 N) x (13 m) = 1,950 joules .
6 0
4 years ago
The statement that "the lowest energy configuration for an atom is the one having the maximum number of unpaired electrons allow
LUCKY_DIMON [66]

Answer:

Hund's rule

Explanation:

Hund's rule is defined as the rule whose first rule in the chemistry says that, for a given electronic configuration, the term which posses lowest energy has maximum multiplicity. The multiplicity is defined as the tem 2S+1, where S is the total spin angular momentum.

Therefore, the term which has lowest energy that term posses maximum number of S.

Hund's rule of maximum multiplicity: Electron present in same energy orbitals firstly they completed half orbit than start pairing.

Therefore, the energy of lowest configuration for an atom is the one having the maximum number of unpaired electron which is allowed by the Pauli principle in a particular set of degenerate orbit is called Hund's rule.

8 0
3 years ago
Read 2 more answers
A burning piece of wood converts ____ energy into ____ energy​
liq [111]

Answer:

a burning piece of converts Chemical energy into Heat(Thermal) and Light energy

8 0
3 years ago
A charge Q experiences no net force at a particular point in space. Which of the following situations described below must ALWAY
laila [671]

Answer:

-There are no other charges nearby.

Explanation:

-There are no other charges nearby.

If there is no net charge in nearby space then the force on this charge will be ZERO

-If there are other charges nearby, they must all have the same sign as Q.

There there is nearby charge of same sign then it will have repulsion force on Q

-If there are other charges nearby, they must all have the opposite sign of Q.

if there is nearby charge of opposite sign then the force must be attraction force.

-If there are other charges nearby, the total positive charge must equal the total negative charge.

If there exist two type of charges nearby then there may exist either attraction or repulsion force on it

8 0
4 years ago
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