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Sliva [168]
3 years ago
10

A man pushes a 10-kg block 10 m, along a rough, horizontal

Physics
1 answer:
abruzzese [7]3 years ago
8 0

Answer:

hope you can understand

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A boy at a football field practice kicked a 0.500-kg ball with a force of 100N. How fast will the ball move after reaching a dis
Tpy6a [65]

Answer:

v(7) = 52.915 m/s

Explanation:

First, find the value for acceleration.

F = ma

100 = .5 * a

a = 200 m/s²

Next find the velocity at x = 7 using kinematic equations.

v² = v₀² + 2a(Δx)

v² = (0)² + 2(200)(7)

v = \sqrt{2800}

v = 52.915 m/s

3 0
3 years ago
A wire delivers 120 C of charge in 40 s.
Neporo4naja [7]

Answer:

3 A

Explanation:

Charge is a product of current and time, expressed as Q=It where Q is charge in Coulombs, I is current in Amperes and t is time taken in seconds. Making I the subject of the formula then I=\frac {Q}{t}

Substituting 120 C for charge and 40 s for t thenI=\frac {120}{40}=3\ A

From the choices given, it appears that time should have been 4 s to get option A or alternatively charge should have been 1200 C

3 0
3 years ago
Connor is a basketball player who makes, on average, 65% of her free throws. Asume each shot is independent. SHOW ALL WORK FOR F
baherus [9]

Answer:

DUNNO

Explanation:

BIT BAD FOR 65% WOULD GET -100%

6 0
3 years ago
The radius of the earth's very nearly circular orbit around the sun is 1.5 1011 m. find the magnitude of the earth's velocity, a
kotykmax [81]
The radius of Earth's circular trajectory is
R=1.5*10^{11} m
The time for the Earth to travel around the Sun is
t=365(days)*24(hours)*3600(seconds) =3.1536*10^7 (s)
Thus the velocity is velocity
v=2\pi R/t =2\pi *1.5*10^{11}/(3.1536*10^{7})=2.99*10^4 (m/s)
From this we can deduce the centripetal acceleration
a=v^2/R =(2.99*10^4)^2/(1.5*10^{11}) =5.96*10^{-3}  (m/s^2)
Angular velocity is
\omega =v/R =(2.99*10^4)/(1.5*10^{11})=2*10^{-7} (rad/s)

5 0
4 years ago
Which of the following is NOT a
Liula [17]

Answer:B

Explanation:

6 0
4 years ago
Read 2 more answers
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