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3 years ago

What happens to raisins or other dried fruits in breakfast cereals when you pour milk over them? why?

1 answer:

8 0

Dried fruits and raisins get terribly soggy after being drenched in milk for a long period of time. They act like a sponge, absorbing all of the milk up making them wet and "soggy". I prefer them to be like that when I eat my cereal in the morning.

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[Then mother noticed that two children who are watching the game are sick and coughing.She told her son to keep distance from th

Andrew [12]

Answer:

in illustration 1

the mother told her son not to play with the boy having cough because it is a transferable disease which could cause him also to get sick and would get cough.

while in

illustration 2

the mother let the boy play with the boy having asthma because it is not a transferable disease which wold not affect him or any one else.

Explanation:

this is the reason

7 0

3 years ago

Read 2 more answers

In the combined gas law, if the volume is decreased, what happens to the temperature if pressure remains constant?

Flura [38]

The correct answer is A. In the combined gas law, if the volume is decreased and the pressure is constant, then the temperature decreases.

P1V1/ T1 = P2V2 / T2

Assume the volume decrease by half; V2 = V1/2

P1V1/ T1 = P2V1 /2 T2

Cancelling terms,

1/T1 = 1/2 T2

T2 = T1/2

Thus, the temperature decreased.

8 0

4 years ago

A 5g piece of aluminum foil (c=0.897) at 100°C is dropped into a 25g container of water (c=4.184) at 20°C. What is the final tem

jeyben [28]

Answer:

23.6°C

Explanation:

use delta h method

5 0

3 years ago

What is the mass of the solid NH4Cl formed when 75.5 g of NH3 is mixed with an equal mass of HCl? What is the volume of the gas

Gekata [30.6K]

Answer : The volume of the gas remaining is 56.5 liters.

The gas is hydrochloric acid and the formula of the gas is HCl.

The mass of $NH_4Cl$ produced is, 110.7 grams.

Explanation :

The balanced chemical reaction will be:

$NH_3+HCl\rightarrow NH_4Cl$

First we have to calculate the moles of $NH_3$ and HCl

$\text{Moles of }NH_3=\frac{\text{Mass of }NH_3}{\text{Molar mass of }NH_3}$

Molar mass of NH_3 = 17 g/mole

$\text{Moles of }NH_3=\frac{75.5g}{17g/mole}=4.44mole$

and,

$\text{Moles of }HCl=\frac{\text{Mass of }HCl}{\text{Molar mass of }HCl}$

Molar mass of HCl = 36.5 g/mole

$\text{Moles of }HCl=\frac{75.5g}{36.5g/mole}=2.07mole$

Now we have to calculate the limiting and excess reagent.

From the balanced reaction we conclude that

As, 1 mole of HCl react with 1 mole of $NH_3$

So, 2.07 mole of HCl react with 2.07 mole of $NH_3$

From this we conclude that, $NH_3$ is an excess reagent because the given moles are greater than the required moles and HCl is a limiting reagent and it limits the formation of product.

The remaining moles of HCl gas = 4.44 - 2.07 = 2.37 moles

Now we have to calculate the volume of the gas remaining.

Using ideal gas equation :

PV = nRT

where,

P = Pressure of gas = 752 mmHg = 0.989 atm (1 atm = 760 mmHg)

V = Volume of gas = ?

n = number of moles of gas = 2.37 moles

R = Gas constant = 0.0821 L.atm/mol.K

T = Temperature of gas = $14.0^oC=273+14.0=287K$

Putting values in above equation, we get:

$0.989atm\times V=2.37mole\times (0.0821L.atm/mol.K)\times 287K$

V = 56.5 L

Now we have to calculate the moles of $NH_4Cl$

As, 1 mole of HCl react with 1 mole of $NH_4Cl$

So, 2.07 mole of HCl react with 2.07 mole of $NH_4Cl$

Now we have to calculate the mass of $NH_4Cl$

$\text{ Mass of }NH_4Cl=\text{ Moles of }NH_4Cl\times \text{ Molar mass of }NH_4Cl$

Molar mass of $NH_4Cl$ = 53.5 g/mole

$\text{ Mass of }NH_4Cl=(2.07moles)\times (53.5g/mole)=110.7g$

Thus, the volume of the gas remaining is 56.5 liters.

The gas is hydrochloric acid and the formula of the gas is HCl.

The mass of $NH_4Cl$ produced is, 110.7 grams.

3 0

3 years ago

Could anyone help me with question 3?

Gwar [14]

Second one i think.......

3 0

3 years ago