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xxTIMURxx [149]
4 years ago
9

3.

Chemistry
1 answer:
Katena32 [7]4 years ago
6 0

Answer:

it's A endothermic its when two objects rub each other to form heat this is also known as friction force

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Does the density of an object depend on its size? Explain?.
evablogger [386]

No, the density of an object does not depend on its size.

A piece of glass with a volume of 10 cm³ may have a mass of 27 g. Its density is  

<em>D</em> = <em>m</em>/<em>V</em> = 27 g/10 cm³ = 2.7 g/cm³

A piece of the same type of glass with a volume of 20 cm³ will have a mass

of 54 g. Its density is  

<em>D</em> = <em>m</em>/<em>V</em> = 54 g/20 cm³ = 2.7 g/cm³

Thus, density does not change with the size of an object. Density is an <em>intensive property</em>.

3 0
3 years ago
Which statement supports the fact that radioactive isotopes are useful in medicine?
Nastasia [14]

elements using your lessons and experience within this virtual lab. 150 words max   its a

4 0
3 years ago
Read 2 more answers
A hydrogen-filled balloon was ignited and 1.80 g of hydrogen reacted with 14.4 g of oxygen.
Alex777 [14]
You will get 16.2g of water
4 0
3 years ago
Calculate the final temperature of the system: A 50.0 gram sample of water initially at 100 °C and a 100 gram sample initially a
katrin2010 [14]

Answer:

The final temperature of the system is 42.46°C.

Explanation:

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c\times (T_f-T_1)=-(m_2\times c\times (T_f-T_2))

where,

c = specific heat of water= 4.18J/g^oC

m_1 = mass of water sample with 100 °C= 50.0 g

m_2 = mass of water sample with 13.7 °C= 100.0 g

T_f = final temperature of system

T_1 = initial temperature of 50 g of water sample= 100^oC

T_2 = initial temperature of 100 g of water =13.7^oC

Now put all the given values in the given formula, we get

50.0 g\times 4.184 J/g^oC\times (T_f-100^oC)=-(100 g\times 4.184 J/g^oC\times (T_f-13.7^oC))

T_f=42.46^oC

The final temperature of the system is 42.46°C.

5 0
3 years ago
1.5 of potassium ioxcide in 150cm^3 of solution
lara [203]

Answer:

Explanation:

I'm not sure what is being asked, not the units of "1.5."  I don't know of potassium "ioxicide."  Was "dioxide" intended?

I'll assume the question is "What is the concentration, in Molar, of 1.5g of potassium dioxide in 150cm^3 of water (150cm^3 is 150 ml).

The molar mass of K2O, potassium dioxide, is 94.2 g/mole.  1.5g is (1.5g/94.2 g/mole) or 0.0159 moles of K2O.  The definition of Molar is moles/liter.  So take the moles of K2O and divide by the liters, which is 0.150L in this case.

(0.0159 moles K2)/0.150 L  = 0.106 M K2O

7 0
3 years ago
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