The mass of ethanol present in the vapor is 8.8×10⁻²g. when liquid and vapor ethanol at equilibrium.
The volume of the bottle = 4.7 L
Mass of ethanol = 0.33 g
Temperature (T1) = -11 oC = 273-11 = 262 K
P1 = 6.65 torr
Now we will calculate the mole by applying the ideal gas equation:-
PV = nRT
Or, n = PV/RT
Where P is the pressure
T is the temperature
R is the gas constant = 0.0821 L atm mol-1K-1
V is the volume
Substituting the values of P, V, T, and R the mole of ethanol is calculated as:-
= 0.001913 mol C2H6
Conversion of the mole to gm
Molar mass of ethanol (M) = 46.07 g/mol
Mass of C2H6O =0.001913 mol C2H6O 46.07 g/mol = 0.088 = 8.8×10⁻²g.
Hence, the mass of ethanol present in the vapor is found to be 8.8×10⁻²g.
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Becuase they need special equipment and things like that that may not be available in the state i think
The chemical formula of the ionic compound is XY₂.
<h3>Ionic compounds</h3>
- Ionic compounds are compounds which are formed from the combination of negatively charged and positively charged ion.
- Positively charged ions are formed by loss of electrons
- Negatively-charged ions are formed from gain of electrons
<h3>Formation of ionic compounds</h3>
During the formation of the ionic compound between an ion X that has a charge of 2+ and ion Y has a charge of 1-, two negatively charged ions of Y are required to form a neutral ionic ionic compound when they react with X.
The chemical the formula of the ionic compound they form is as follows;
X²⁺ + 2Y⁻ ---> XY₂
Therefore, the chemical formula of the ionic compound is XY₂.
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Answer:
a molecule with two of the same element
Explanation:
