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ch4aika [34]
3 years ago
15

What are the lessons that you learn from nature​

Chemistry
2 answers:
Daniel [21]3 years ago
7 0

Answer:

Nature is important

Explanation:

Nesterboy [21]3 years ago
3 0
To appreciate small things,
like how flowers appreciate it when bees pollinate them, or how animals appreciate it when people feed them
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Which statements are true of fossil fuels?
Arisa [49]
Letters A and B are correct because burning fossil fuels can harm the atmosphere through the greenhouse effect and contribute to global warming, and can sometimes spill into the water and harm the environment.
7 0
3 years ago
A material has a volume of 63.0 cm3 and a mass of 28 grams.  What is the density of the material in g/cm3 to the correct number
dimaraw [331]

Answer:

0.4444 g/cm³ ≅ 0.44 g/cm³ (2 significant figures).

Explanation:

  • Knowing that:

<em>d = m/V,</em>

where, d is the density of the material (g/cm³).

m is the mass of the material (m = 28 g).

V is the volume of the material (V = 63.0 cm³).

<em>∴ d = m/V </em>= (28 g)/(63.0 cm³) = <em>0.4444 g/cm³ ≅ 0.44 g/cm³ (2 significant figures).</em>

7 0
3 years ago
Fire extinguishers that spray carbon dioxide on the fire, work very effectively because it forms a blanket around the burning ma
Arte-miy333 [17]

Answer:

I think it will option B it will retain enough heat

8 0
3 years ago
) B5H9(l) is a colorless liquid that will explode when exposed to oxygen. How much heat is released when 0.211 mol of B5H9 react
Tom [10]

<u>Answer:</u> The amount of heat released when 0.211 moles of B_5H_9(l) reacts is 554.8 kJ

<u>Explanation:</u>

The chemical equation for the reaction of B_5H_9 with oxygen gas follows:

2B_5H_9(l)+12O_2(g)\rightarrow 5B_2O_3(s)+9H_2O(l)

The equation for the enthalpy change of the above reaction is:

\Delta H_{rxn}=[(5\times \Delta H_f_{(B_2O_3(s))})+(9\times \Delta H_f_{(H_2O(l))})]-[(2\times \Delta H_f_{(B_5H_9(l))})+(12\times \Delta H_f_{(O_2(g))})]

We are given:

\Delta H_f_{(H_2O(l))}=-285.4kJ/mol\\\Delta H_f_{(B_2O_3(s))}=-1272kJ/mol\\\Delta H_f_{(B_5H_9(l))}=73.2kJ/mol\\\Delta H_f_{(O_2(g))}=0kJ/mol

Putting values in above equation, we get:

\Delta H_{rxn}=[(2\times (-1272))+(9\times (-285.4))]-[(2\times (73.2))+(12\times (0))]\\\\\Delta H_{rxn}=-5259kJ

To calculate the amount of heat released for the given amount of B_5H_9(l), we use unitary method, we get:

When 2 moles of B_5H_9(l) reacts, the amount of heat released is 5259 kJ

So, when 0.211 moles of B_5H_9(l) will react, the amount of heat released will be = \frac{5259}{2}\times 0.211=554.8kJ

Hence, the amount of heat released when 0.211 moles of B_5H_9(l) reacts is 554.8 kJ

7 0
3 years ago
Which step will decrease the pressure of a gas inside a closed cubical container?
ANTONII [103]

Answer:lol

Explanation:

7 0
3 years ago
Read 2 more answers
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