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2 years ago

What are the lessons that you learn from nature

Chemistry

2 answers:

Daniel [21]2 years ago

7 0

Answer:

Nature is important

Explanation:

Nesterboy [21]2 years ago

3 0

To appreciate small things,
like how flowers appreciate it when bees pollinate them, or how animals appreciate it when people feed them

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Answer:

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2 years ago

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What type of ions do metals produce?

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Ionic bonds

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3 years ago

How many total electrons can enter the set of 3p orbitals? a. 3 b. 10 c. 2 d. 6

Sliva [168]

Answer:

For n=3 and l=1=p

It is 3p-orbital.

Magnetic quantum number m

have values from -l to +l and total of 2l+1 values.

Forl=1, m

values are:

=−1,0,1 for l=1; total m

values =3= Number of orbitals

Each orbital can occupy maximum of two electron

Number of electrons =2×3=6

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Number of elements with last electron in 3p orbitals = 6

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3 years ago

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kirill115 [55]

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3 years ago

When 6.040 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 18.95 grams of CO2 and 7.759 grams of H

algol [13]

Answer: The empirical formula is $CH_2$ and molecular formula is $C_4H_8$

Explanation:

We are given:

Mass of $CO_2$ = 18.95 g

Mass of $H_2O$ = 7.759 g

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 18.59 g of carbon dioxide, = $\frac{12}{44}\times 18.59=5.07g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 7.759 g of water, = $\frac{2}{18}\times 7.759=0.862g$ of hydrogen will be contained.

Mass of C = 5.07 g

Mass of H = 0.862 g

Step 1 : convert given masses into moles.

Moles of C = $\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{5.07g}{12g/mole}=0.422moles$

Moles of H= $\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.862g}{1g/mole}=0.862moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = $\frac{0.422}{0.422}=1$

For H = $\frac{0.862}{0.422}=2$

The ratio of C : H = 1: 2

Hence the empirical formula is $CH_2$ .

The empirical weight of $CH_2$ = 1(12)+2(1)= 14 g.

The molecular weight = 56.1 g/mole

Now we have to calculate the molecular formula.

$n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{56.1}{14}=4$

The molecular formula will be= $4\times CH_2=C_4H_8$

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2 years ago

What are the lessons that you learn from nature​

What are the lessons that you learn from nature