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PSYCHO15rus [73]
3 years ago
13

I WILL MARK BRAINIEST PLEASE HELP QUICKLY!!

Chemistry
1 answer:
omeli [17]3 years ago
4 0

Answer:

6CO2 + 6H2O → C6H12O6 + 6O2 is a balanced equation

Explanation:

Carbon, Oxygen, Hydrogen

Reactants are carbon dioxide and water, products are glucose and oxygen

Dynamic Equilibrium I have no idea about (soz)

I believe this might be endothermic

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The equilibrium expression for kp for the reaction below is __________. n2 (g) o2 (g) 2no (g)
PolarNik [594]
For the reaction;
N2(g) + O2(g) = 2NO(g)

Kp = pNO²/ pN₂pO₂; (No units)
where;
pNO is the partial pressure of NO;
pN₂ is the partial pressure of nitrogen
pO₂ is the partial pressure of Oxygen
The equilibrium constant  Kp is deduced from the balanced chemical equation for a reversible reaction, NOT experimental data as is the case for rate expressions in kinetics. 
Kp changes with temperature considerably changing the position of an equilibrium, and, at a constant temperature, and therefore constant K, the position of an equilibrium can change significantly depending on relative concentrations/pressures of 'reactants' and 'products'.
8 0
3 years ago
Activation energy Group of answer choices is only required in catabolic reactions that release energy. is not required at all wh
daser333 [38]

Answer:

is used to break reactant bonds and/or make new product bonds.

Explanation:

<em>The correct answer would be that </em><em>activation energy is used to break reactant bonds and/or make new product bonds</em><em>.</em>

The <u>activation energy is the minimum energy that must be overcome by the reactants in a reaction in other to become products</u>. In order for products to be formed, the bonds between reactants must be broken and new ones must be formed to arrive at the products. In other words, the activation energy can be seen as the energy required to break the bonds between reactants and form the bonds between products during the course of a reaction.

<em>Activation energy is required even in the presence of enzymes. The latter only catalyzes reactions by lowering the minimum energy required to break the bonds between reactants and form new ones between products</em>.

5 0
3 years ago
Identify the types of intermolecular forces present in each of the following substances, and select the substance in each pair t
Sergeu [11.5K]

Answer:

a. Van der Waals forces, C8H18 has higher boiling point.

b. Van der Waals forces in both compounds

    Dipole -Dipole in CH3OCH3

c. Van der Waals  and dipole-dipole in both, higher boiling point for  HOOH.

Additionally H bonding in HOOH

d. Van der Waals for both compounds,  additionally dipole- dipole and hydrogen bonding for  NH2NH2.

Higher boling point NH2NH2

Explanation:

To answer this question we have to know the hybridization of the atoms of interest and/or the presence of resultant dipole moments which make the molecule polar, and the van der Waals interactions. Also we have to look for the presence of hydrogen bonding.

Remember van der Waals forces will be present in all of the molecules since they are of the instantaneous type produced by the momentaneous distortions of the electron clouds.

a. These two compounds are hydrocarbons, the electronegativity difference between carbon and hydrogen is very small, so the only factor we need to consider are the van der Waals interactions.

The van der Waals interactions increase with molecular weight since they are interactions which are momentaneous between the atoms in the molecule, and the heavier the molecule the more these distortions are possible.

Since C8H18 has a higher molecular than C6H14, it follows it has a greater boiling point.

b. CH3OCH3  differs only on the added O atom to C3H8. They have similar molecular weights, 46 vs 44 g/mol, but the presence of the tehedral sp³ hybridized oxygen atom with its high electronegativity produces dipole moments and imparts a polarity to the molecule which make us to predict  CH3OCH3 will have a higher boiling point.

c.  In HOOH we have dipole-dipole moments since the oxygen atom is sp³ hybridized and the O-O-H is tetrahedral, the molecule is polar. Additionally we have the presence of H bond in this compound which is not possible in HSSH.

While the molecule HSSH is also polar since it has two dipole moments in the sp³ hybridized ( tetrahedral ) S,  it is not as big as the dipole moment in O-H.

Therefore Hydrogen peroxide, HOOH, has a higher boiling point than HSSH

d. The N-H bond has a dipole moment, and since the N is tetrahedral there is a resultant dipole moment. As in case d., we have hydrogen bonding  between H and N.

NH2NH2 then will have a higher boiling point than CH3CH3 where only van der Waals interactions are possible.

You are welcome.

8 0
4 years ago
What’s the mass of a substance that’s density is 100.09g/mL and takes up 52.75mL?
Leokris [45]
Answer: 5,279.7475g

Mass = Density x Volume
Fill in the blanks :D
Mass= 100.09g/mL x 52.75mL

The mL cancels out and you multiply the numbers.
Mass= 5,279.7475 g
5 0
3 years ago
1 Point
azamat

Answer:

XY → X + Y general reaction represents a decomposition reaction where a molecule is “broken” in two separate molecules

Explanation:

In a double-displacement reaction two molecules will exchange atoms or group of atoms, and it should look like this:

XY + AB →  XA + YB

In a combustion reaction molecules are reacting with oxygen generating oxides.  

XY + O_{2} → XO + YO

In a single-displacement reaction an atom or a group of atoms in a molecule are replaced by other atoms, and it should look like this:

XY + A → XA + Y

8 0
3 years ago
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