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4 years ago

A ________ stream pattern develops on lands underlain by tilted or folded, alternating hard and soft, sedimentary strata.

1 answer:

4 0

The answer in this question is trellis in which define in this statement as the stream pattern which develops on lands underlain by the tilted or folded, alternating hard and soft and sedimentary strata is trellis. Trellis in architecture is an archintectural structure that is usually made from an open framework or lattice of interwoven or intersecting pieces of wood, bamboo or metal.

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You are called to the crime scene immediately and you begin your investigation at 2 PM. The first thing you do is take the tempe

adell [148]

As per Newton's law of cooling we know that

$\frac{\Delta T}{dt} = k(T_avg - T_s)$

in 5 hours the body temperature becomes 79.6 from 84.4

while the surrounding temperature is given as 68 degree F

now from above formula

$\frac{84.4 - 79.6}{5} = k (\frac{84.4 + 79.6}{2} - 68)$

$0.96 = k(14)$

now let say the person died "t" time ago

now we will have

$\frac{98.6 - 84.4}{t} = k (\frac{98.6 + 84.4}{2} - 68)$

$\frac{14.2}{t} = k(23.5)$

$\frac{14.2}{t} = \frac{0.96}{14}(23.5)$

$t = 8.8 hours = 9hours (approx)$

so he died at approx 5 Am in morning

5 0

3 years ago

Assume that, as the battery wears out, the voltage decreases at 0.03 volts per second and, as the resistor heats up, the resista

liraira [26]

Answer:

$\frac{dI}{dt} =-3*10^-^4amps/sec$

Explanation:

From the question we are told that

Voltage decreases at $\frac{dv}{dt} =-0.03volts/sec$

Resistance increase at $\frac{dR}{dt}=0.02ohms /sec$

Resistance at $R=100ohms$

Current at $I=0.02amps$

Generally the equation for ohms law is mathematically represented as

$V=IR$

Therefore

$\frac{dV}{dt} =R\frac{dI}{dt} +I\frac{dR}{dt}$

Generally making $\frac{dI}{dt}$ subject of the formula in the above equation mathematically gives

$\frac{dV}{dt} =R\frac{dI}{dt} +I\frac{dR}{dt}$

$R\frac{dI}{dt} = \frac{dV}{dt} -I\frac{dR}{dt}$

$\frac{dI}{dt} =\frac{1}{R} (\frac{dV}{dt} -I\frac{dR}{dt})$

Therefore

$\frac{dI}{dt} =\frac{1}{100}((-0.03) -(0.02)*(0.02))$

Generally it is given that the change in current is

$\frac{dI}{dt} =-3*10^-^4amps/sec$

8 0

3 years ago

You are driving at 30.0 m/s on a freeway curve of radius 25.0 m. What is the magnitude of your acceleration?

mote1985 [20]

Answer:

36.0 m/s^2

Explanation:

4 0

3 years ago

A spring of negligible mass stretches 3.00 cm from its relaxed length when a force of 7.50 N is applied. A 0.500-kg particle res

zhannawk [14.2K]

Answer:

a) 250 N/m

b) 22.4 rad/s , 3.6 Hz , 0.28 sec

c) 0.3125 J

Explanation:

F = force applied on the spring = 7.50 N

x = stretch of the spring from relaxed length when force "F" is applied = 3 cm = 0.03 m

k = spring constant of the spring

Since the force applied causes the spring to stretch

F = k x

7.50 = k (0.03)

k = 250 N/m

m = mass of the particle attached to the spring = 0.500 kg

Angular frequency of motion is given as

$w = \sqrt{\frac{k}{m}}$

$w = \sqrt{\frac{250}{0.5}}$

$w$ = 22.4 rad/s

$f$ = frequency

Angular frequency is also given as

$w$ = 2 π $f$

22.4 = 2 (3.14) f

$f$ = 3.6 Hz

$T$ = Time period

Time period is given as

$T = \frac{1}{f}$

$T = \frac{1}{3.6}$

$T$ = 0.28 sec

A = amplitude of motion = 5 cm = 0.05 m

Total energy of the spring-block system is given as

U = (0.5) k A²

U = (0.5) (250) (0.05)²

U = 0.3125 J

5 0

4 years ago

imagine that a new planet is discovered with two moons of equal mass, moon A and moon B. The mass of the new planet is greater t

sdas [7]

The gravitational pull on moon A will be lower since it is further away from the new planet.

3 0

4 years ago

Read 2 more answers