All categories

4 years ago

A ________ stream pattern develops on lands underlain by tilted or folded, alternating hard and soft, sedimentary strata.

1 answer:

4 0

The answer in this question is trellis in which define in this statement as the stream pattern which develops on lands underlain by the tilted or folded, alternating hard and soft and sedimentary strata is trellis. Trellis in architecture is an archintectural structure that is usually made from an open framework or lattice of interwoven or intersecting pieces of wood, bamboo or metal.

You might be interested in

A raft is made using a number of logs (TBD) with 25-cm diameter and 2-m-length. It is desired that a maximum 90 percent volume o

Vilka [71]

Answer:

6logs

Explanation:f

First finding the volume of the logs

V= π/4d²l

= 0.098m³

So number of logs will be

Weight of 2 boys + weight of log = buoyancy force.

2( 400)+ N ( Mlog x g) = density of water x volume displaced x g

2(400) = N x 0.098x 1000x 9.8 x 0.9- 0.75* 1000

N= 5.5 which is approx 6logs

3 0

3 years ago

A charge q = 3 × 10-6 C of mass m = 2 × 10-6 kg, and speed v = 5 × 106 m/s enters a uniform magnetic field. The mass experiences

NeX [460]

Answer:

Magnetic field, B = 0.004 mT

Explanation:

It is given that,

Charge, $q=3\times 10^{-6}\ C$

Mass of charge particle, $m=2\times 10^{-6}\ C$

Speed, $v=5\times 10^{6}\ m/s$

Acceleration, $a=3\times 10^{4}\ m/s^2$

We need to find the minimum magnetic field that would produce such an acceleration. So,

$ma=qvB\ sin\theta$

For minimum magnetic field,

$ma=qvB$

$B=\dfrac{ma}{qv}$

$B=\dfrac{2\times 10^{-6}\ C\times 3\times 10^{4}\ m/s^2}{3\times 10^{-6}\ C\times 5\times 10^{6}\ m/s}$

B = 0.004 T

B = 4 mT

So, the magnetic field produce such an acceleration at 4 mT. Hence, this is the required solution.

4 0

3 years ago

6) If nuclei A has a probability P of decaying in time t and nucleus B has a probability 2p of decaying in time t, which stateme

vredina [299]

Answer:

sorry dont know so so sorry

6 0

3 years ago

Which of these is a likely impact of stronger than normal trade winds on the eastern Pacific Ocean?

Bas_tet [7]

Answer:

Jet stream would be displaced southwards causing heavy rain and flooding.

Explanation:

The other options of the question were A) Jet stream would be displaced northwards causing drought. B) Jet stream would be displaced southwards causing drought. D) Jet stream would be displaced northwards causing heavy rain and flooding,

The statement that is a likely impact of stronger than normal trade winds in the Pacific Northwest to the United States is "Jet stream would be displaced southwards causing heavy rain and flooding."

We are talking about climate or weather terminology. In this case, we are referring to the "El Niño" (the Children) effect. Its presence affects the weather in North America. This phenomenon combines with the "La Niña) effect and it presents itself every two to seven years, ad they last from 8 to 12 months, affecting the weather conditions of the region.

3 0

3 years ago

Read 2 more answers

The surface charge density on an infinite charged plane is −1.70 x 10^−6 C/m^2 . A proton is shot straight away from the plane a

goldfiish [28.3K]

Answer:

Acceleration of proton will be $-9.197\times 10^{12}m/sec^2$

Explanation:

We have given surface charge density of an infinite charged plate $\sigma = -1.70\times 10^{-6}C/m^2$

Electric field due to infinite sheet charge is given by $E=\frac{\sigma }{2\epsilon _0}=\frac{-1.7\times 10^{-6}}{2\times 8.85\times10^{-12}}=-0.096\times 10^6=-9.6\times 10^4N/C$

Charge in proton is given by $e=1.6\times 10^{-19}C$

So force on proton $F=qE=1.6\times 10^{-19}\times -9.6\times 10^4=-15.36\times 10^{-15}N$

Mass of proton $m=1.67\times 10^{-27}kg$

According to newtons second law force F = mass × acceleration

So $-15.36\times10^{-15}=1.67\times 10^{-27}a$

$a=-9.197\times 10^{12}m/sec^2$

3 0

3 years ago