Answer:
2.271386111 km/s
Explanation:
1321÷60hrs÷60mins×6.19s=2.27km
When light is incident parallel to the principal axis and then strikes a lens, the light will refract through the focal point on the opposite side of the lens.
To find the answer, we have to know about the rules followed by drawing ray-diagram.
<h3>What are the rules obeyed by light rays?</h3>
- If the incident ray is parallel to the principal axis, the refracted ray will pass through the opposite side's focus.
- The refracted ray becomes parallel to the major axis if the incident ray passes through the focus.
- The refracted ray follows the same path if the incident light passes through the center of the curve.
Thus, we can conclude that, when light is incident parallel to the principal axis and then strikes a lens, the light will refract through the focal point on the opposite side of the lens.
Learn more about refraction by a lens here:
brainly.com/question/13095658
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Answer:
w = 0.173 N
Explanation:
The weigh of any object is computed by multiplying its mass to the acceleration of gravity, so we need to find the gravity on that planet in order to compute the weigh we want.
The ball has a mass of 0.1 kg and its released from a height of 10 m, therefore it is in a free fall motion with gravity acting as a constant acceleration on the body, we can use the equations for free fall movement in order to determine the value for this acceleration:
y(t) = v_0 * t + y_0 - 0.5 * g * t^2
y(t) is the position in the end of the movement, when t = 3.4 s, so y(t) = 0 m.
v_0 is the initial velocity, in this case v_0 = 0 m/s.
y_0 is the initial position of the ball, in this case it is 10 m.
g is the gravity that we want to know.
Applying these values in the equation we have:
0 = 0*(3.4) + 10 - 0.5*g*(3.4)^2
0 = 10 - 0.5*11.56*g
0 = 10 -5.78*g
5.78*g = 10
g = 1.73 m/s^2
Then we can use this value to find out the weigh of the ball in that planet:
w = g*m = 0.1*1.73 = 0.173 N
<h3>The Answer is:</h3>
(B)Find out how much space (V)
of the room was occupied by it.
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