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kozerog [31]
3 years ago
12

How much force is needed to accelerate a 1000Kg car at a rate of 3m/s2?

Physics
2 answers:
11111nata11111 [884]3 years ago
8 0
F=force
M=mass
A=acceleration
F= M×A
F=1000×3
f=3000 kgm/s2
force required to accelerate car .
ikadub [295]3 years ago
6 0

According to Newton (2nd law),   Force = (mass) x (acceleration)

Substitute what we know :           Force = (1,000 kg) x (3 m/s²)

Do the arithmetic:                        Force = 3,000 kg-m/s²  =  3,000 newtons

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A pebble is thrown into the air with a velocity of 19/m at an angle of 36 with respect to the horizontal.
kow [346]

Answer:

The maximum height the pebble reaches is approximately;

A. 6.4 m

Explanation:

The question is with regards to projectile motion of an object

The given parameters are;

The initial velocity of the pebble, u = 19 m/s

The angle the projectile path of the pebble makes with the horizontal, θ = 36°

The maximum height of a projectile, h_{max}, is given by the following equation;

h_{max} = \dfrac{\left (u \times sin(\theta) \right)^2}{2 \cdot g}

Therefore, substituting the known values for the pebble, we have;

h_{max} = \dfrac{\left (19 \times sin(36 ^{\circ}) \right)^2}{2 \times 9.8} = 6.3633894140470403035477570509439

Therefore, the maximum height of the pebble projectile, h_{max} ≈ 6.4 m.

3 0
3 years ago
does it require more energy to brew 12 cups with the coffee-maker or reheat 12 cups of coffee in a microwave?
Leni [432]
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What is the pressure exerted by an elephant who weighs 2500N and whose feet cover an area of 7.5m2?
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Answer:

0.00339905404

Explanation:

kg: 0.00339905404

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pounds: 0.0483459126

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3 years ago
A ski lift has a one-way length of 1 km and a vertical rise of 200 m. The chairs are spaced 20 m apart, and each chair can seat
RSB [31]

Answer:

Explanation:

The question states that the chairs are spaced 20 m apart through a length of 1 km, or say, 1000 m.

It also does say that each chair weighs 250 kg, and as such the load is

M = 50 * 250

M = 12500.

Taking into consideration, the initial and final heights, we have

h1 = 0, h2 = 200 m

The work needed to raise the chairs,

W = mgh, where h = h2 - h1

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W = 2.54*10^7 J

The work is done at a rate of 10 km/h, and at a distance of 1 km, time taken would be

t = 1/10 = 0.1 h or say, 360 s

The power needed thus, is

P = W/t

P = 2.54*10^7 / 360

P = 68125 W, or 68 kW

Initial velocity, u = 0 m/s

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Startup time, t is 17 s

Acceleration during the startup then is

a = (v - u)/t

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The power needed for the acceleration is

P = ½m [(v² - u²)/t]

P = ½ * 12500 * [2.78²/17]

P = 6250 * 0.455

P = 2844 W

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3 years ago
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