You are crossing the event horizon of a black hole
When you are feeling like spaghetti and you are normally only about 2 meters tall, you are now about 25 meters long, then look up over your head, you see things moving pretty quickly in the universe but that lasts only a brief instant, and then all contact with the universe is lost, you are crossing the event horizon of a black hole.
<h3>What happens when you are crossing the event horizon of a black hole?</h3>
- The point of no return is the black hole's event horizon.
- Anything that continues beyond this point will be absorbed by the black hole and disappear from the known universe forever.
- The black hole's gravity is so strong at the event horizon that it cannot be overcome or resisted by any mechanical force.
<h3>Is it possible to endure inside an event horizon?</h3>
- As a result, the individual would survive and gently float over the event horizon of the black hole without being harmed or stretched into a long, thin noodle.
<h3>What occurs beyond the horizon of the event?</h3>
- A singularity is a truly tiny point that lies beyond the event horizon where gravity is so strong that space-time itself is infinitely bent.
- The principles of physics as they exist presently break down at this point, making any hypotheses about what lies beyond mere conjecture.
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Answer:
Explanation:
l = 600mm = 0.6m
d = 40mm = 0.04m
hd = 30mm = 0.03m (diameter of the hole)
hl = 100mm = 0.1m (hole length)
modulus of elasticity for the aluminium = 85GN/m2
compressive load = 180kN
Answer:
Explanation:
The velocity of a wave in a string is equal to:
v = √(T / (m/L))
where T is the tension and m/L is the mass per length.
To find the mass per length, we need to find the cross-sectional area of the thread.
A = πr² = π/4 d²
A = π (3.0×10⁻⁶ m)²
A = 2.83×10⁻¹¹ m²
So the mass per length is:
m/L = ρA
m/L = (1300 kg/m³) (2.83×10⁻¹¹ m²)
m/L = 3.68×10⁻⁸ kg/m
So the wave velocity is:
v = √(T / (m/L))
v = √(7.0×10⁻³ N / (3.68×10⁻⁸ kg/m))
v ≈ 440 m/s
The speed of sound in air at sea level is around 340 m/s. So the spider will feel the vibration in the thread before it hears the sound.
Answer:
A) 854.46 kPa
Explanation:
P₁ = initial pressure of the gas = 400 kPa
P₂ = final pressure of the gas = ?
T₁ = initial temperature of the gas = 110 K
T₂ = final temperature of the gas = 235 K
Using the equation
Inserting the values
P₂ = 854.46 kPa
Given data:
Yan speed;
Christopher speed;
Christophe starts 30 s later than Yan. Therefore, Christophe takes 30 s less than Yan to reach the same distance.
Part (A)
The distance is given as,
Let both Yan and Christophe meet at d distance from the start position. Therefore,
Substituting all known values,
Therefore, 600 s after Yan's departure Christophe will join him.
Part (B)
The distance is given as,
Substituting all known values,
Therefore, Christophe joins Yan after 6.17 km from the start.
