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Rus_ich [418]
3 years ago
9

A train traveled 350km in 2.5h. what was the average speed of the train?

Physics
2 answers:
Salsk061 [2.6K]3 years ago
4 0

Answer:

The answer is 140km/h

Step by step Explanation:

  • Velocity is the variation in the position of an object in a given time, that is, it is the distance traveled by an object in a unit of time.
  • The velocity is expressed by the formula v = \frac{d}{t}
  • If we replace the values given in the velocity formula we will have:

        v = \frac{350km}{2.5h} \\v = 140 km/h

MaRussiya [10]3 years ago
3 0
Speed equals distance divided by time, so 350 divided by 2.5 equals 140 kilometers per hour.
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To maintain a constant speed, the force provided by a car's engine must equal the drag force plus the force of friction of the r
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Answer:

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Explanation:

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a).

ρ= 1.2 \frac{kg}{m^{3} }, A_{t}= 0.7 m^{2}, D_{t}= 0.28

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F_{t1} = \frac{1}{2} * 0.28 * 0.7m^{2} * 1.2\frac{kg}{m^{3} }* 21.38^{2}= 53.75 N

F_{t1} = \frac{1}{2} * 0.28 * 0.7m^{2} * 1.2\frac{kg}{m^{3} }* 29.44^{2}= 101.92 N

b).

ρ= 1.2 \frac{kg}{m^{3} }, A_{h}= 2.44 m^{2}, D_{h}= 0.57

F_{t1} = \frac{1}{2} * D_{h} * A_{h}* p_{h}* v_{h}^{2}

F_{t1} = \frac{1}{2} * 0.57 * 2.44 m^{2} * 1.2\frac{kg}{m^{3} }* 21.38^{2}= 381.44 N

F_{t1} = \frac{1}{2} * 0.57 * 2.44 m^{2} * 1.2\frac{kg}{m^{3} }* 29.44^{2}= 723.25 N

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3 years ago
What is the velocity of a car if it travels east 340 meters in 10 seconds? V = d/t
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Answer:

The awnser is d

Explanation:

i know cause i took the test

6 0
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Answer:

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3 0
4 years ago
When talking about the speeds of atoms in a gas you must refer to the average speed because
cluponka [151]

Answer:

An Atom's individual speed will change as it collides with other atoms, so we have to use an average.

Explanation:

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Hence, the second option <em>"an Atom's individual speed will change as it collides with other atoms, so we have to use an average" </em>stands correct.

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3 years ago
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