30.6*X+-2.56<br> Pls help

Roseanne and Jackie were asked to design and create a paper airplane that would stay in the air for as long as possible. They be

jekas [21]

Answer:

the planes times in the air

Explanation:

When a paper airplane is thown the path it takes is not the same every time. So, measuring the distance between the points where the airplane took off and the point where is landed would not show the time the plane was in the air.

The weight also does not determine the time the plane was in the air.

So, the planes air time recorded with the stopwatch gives the time the plane was in the air and will indicate the best plane.

6 0

3 years ago

What is the average speed of a car that travels 40 mph for 1 hour and 60 mph in another hour?

svetoff [14.1K]

Average speed = (total distance covered) / (time to cover the distance)

-- Traveling at 40 mph for 1 hour, the distance covered is 40 miles.

-- Traveling at 60 mph for 1 hour, the distance covered is 60 miles.

-- Total distance covered = (40 miles) + (60 miles) = 100 miles

-- Total time = (1 hour) + (1 hour) = 2 hours

-- Average speed = (100 miles) / (2 hours)

<em>Average speed = 50 miles per hour</em>

6 0

3 years ago

What important discovery was made by edmond halley and alexis clairaut, using newton's ideas of mathematics and gravity?

Semmy [17]

They were able to find the orbit of a comet and predict the year of its return.

8 0

3 years ago

Read 2 more answers

A small marble attached to a massless thread is hung from a horizontal support. When the marble is pulled back a small distance

s2008m [1.1K]

Answer:

f' = 2 f

Explanation:

The frequency of the pendulum that swings in simple harmonic motion is given by :

$f={2\pi}\sqrt{\dfrac{l}{g}}$

Where

l is the length of pendulum

g is the acceleration due to gravity

If the length of the thread is increased by a factor of 4, such that, l' = 4 l, let f' is the new frequency such that,

$f'={2\pi}\sqrt{\dfrac{l' }{g}}$

$f'={2\pi}\sqrt{\dfrac{4l}{g}}$

$f'=2\times {2\pi}\sqrt{\dfrac{l}{g}}$

f' = 2 f

So, the new frequency of the pendulum will become 2 time of initial frequency. Hence, the correct option is (b) "2f"

3 0

3 years ago

A steel ball moves from a position of +125 meters to a position of -75 meters. This motion takes 90.0 seconds. What is the veloc

bonufazy [111]

Answer:

2.22m/s to the left

Explanation:

Given parameters:

Initial position = +125m

Final position = -75m

Motion time = 90s

Unknown:

Velocity of the steel ball = ?

Solution:

The velocity of the steel ball is given as the displacement divided by the time;

Velocity = $\frac{displacement}{time}$

The net displacement of the ball = 125- (-75) = 200m to the left

Input the parameters and solve for the velocity;

Velocity = $\frac{200}{90}$ = 2.22m/s to the left

3 0

4 years ago

30.6*X+-2.56 Pls help