2 years ago

30.6*X+-2.56 Pls help

Physics

1 answer:

pochemuha2 years ago

5 0

Answer: 10.16

Explanation:

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To solve the problem it is necessary to apply conservation of the moment and conservation of energy.

By conservation of the moment we know that

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V = Velocity of heavier mass

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v = velocity of lighter mass

That equation in function of the velocity of heavier mass is

$V = \frac{mv}{M}$

Also we have that $m/M = 1/7 times$

On the other hand we have from law of conservation of energy that

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Where,

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Applying this equation in heavier object.

$F_f*S = \frac{1}{2}MV^2$

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$\mu g*S = \frac{1}{2}( \frac{mv}{M})^2$

$\mu = \frac{1}{2} (\frac{1}{7}v)^2$

$\mu = \frac{1}{98}v^2$

$\mu = \frac{1}{g(98)(5.1)}v^2$

Here we can apply the law of conservation of energy for light mass, then

$\mu mgs = \frac{1}{2} mv^2$

Replacing the value of $\mu$

$\frac{1}{g(98)(5.1)}v^2 mgs = \frac{1}{2}mv^2$

Deleting constants,

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In the diagrams, the solid green line represents Earth's rotational axis and the dashed red line represents the magnetic field a

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Any force can affect the momentum of an object
if it changes the object's speed.

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2 years ago

How many excess electrons must be present on each sphere if the magnitude of the force of repulsion between them is 3.33×10−21 n

qwelly [4]

Answer:

The number of excess electrons on each sphere is 759

Explanation:

Given that,

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= 0.20 m

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3.33 × $10^{-21}$ = 9 × $10^{9}$ × (n × 1.602 × $10^{-19}$ )² /0.2²

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3 years ago