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lina2011 [118]
3 years ago
15

Using a 1-kW heater for one hour consumes more energy than using a 100-W bulb for twenty-four hours. Please select the best answ

er from the choices provided
T

F
Physics
1 answer:
Ierofanga [76]3 years ago
8 0
Power is the amount of work done per unit of time. It will have units of Watts which is equal to Joules per second. We determine the energy of each system above by multiplying the power with time. We do as follows:

E(heater) =1000 W (1 hr) (3600s/hr) = 3,600,000 J
E(bulb) = 100 W (24 hr) (3600s/hr) =   8,640,000 J

Therefore, the answer would be false. It is the bulb that consumes more energy.
You might be interested in
A massless, hollow sphere of radius R is entirely filled with a fluid such that its density is p. This same hollow sphere is now
Vesnalui [34]

Answer:

a. 8p

Explanation:

We are given that

Radius of hollow sphere , R1=R

Density of hollow sphere=\rho

After compress

Radius of hollow sphere, R2=R/2

We have to find density of the compressed sphere.

We know that

Density=\frac{mass}{volume}

Mass=Density\times volume=Constant

Therefore,\rho_1 V_1=\rho_2V_2

Volume of sphere=\frac{4}{3}\pi r^3

Using the formula

\rho\times \frac{4}{3}\pi R^3=\rho_2\times \frac{4}{3}\pi (R/2)^3

\rho R^3=\rho_2\times \frac{R^3}{8}

\rho_2=8\rho

Hence, the density of  the compressed sphere=8\rho

Option a is correct.

7 0
2 years ago
A 50,0 g silver spoon at 20.0°C is placed in a cup of coffee at
My name is Ann [436]

The heat capacity of the silver spoon at the given temperature difference is 817.65 J.

<h3>Heat capacity of the silver spoon</h3>

The heat capacity of theb silver spoon is the quantity of heat absorbed by the silver spoon. The heat capacity of the silver spoon at the given temperature difference is calculated as follows;

Q = mcΔθ

where;

  • m is mass of the spoon
  • c is specific heat capacity of silver = 0.237 J/g⁰C
  • Δθ is change in temperature

Q = 50 x 0.237 x (89 - 20)

Q = 817.65 J

Thus, the heat capacity of the silver spoon at the given temperature difference is 817.65 J.

Learn more about heat capacity here: brainly.com/question/16559442

8 0
2 years ago
A fixed coil of wire with 10 turns and an area of 0.055 m2 is placed in a perpendicular magnetic field. This field oscillates in
Blababa [14]

Answer:

Part a)

Average EMF for half cycle is

E_{avg} = 2.64 V

Part b)

For one complete cycle we will have

E_{avg} = 0

Part c)

Maximum induced EMF will be at

t = 0.025 s and 0.075 s

minimum induced EMF is at

t = 0.05s and 0.1 s

Explanation:

As we know that magnetic field is oscillating in direction as well as magnitude

so induced EMF is given as

E = NBA\omega sin(\omega t)

Part a)

For average value of EMF from positive maximum to negative maximum which is equal to half cycle

so we have

E_{avg} = NBA\omega \frac{2}{T}\int_0^{T/2} sin(\omega t) dt

E_{avg} = \frac{2NBA\omega}{\pi}

E_{avg} = \frac{2(10)(0.12)(0.055)(2\pi (10))}{\pi}

E_{avg} = 2.64 V

Part b)

For one complete cycle we will have

E_{avg} = NBA\omega \frac{1}{T}\int_0^T sin(\omega t) dt

E_{avg} = 0

Part c)

Maximum induced EMF will be at

t = \frac{T}{4} and \frac{3T}{4}

here we know

T = \frac{1}{f} = 0.1 s

t = 0.025 s and 0.075 s

minimum induced EMF is at

t = \frac{T}{2} and T

so it is

t = 0.05s and 0.1 s

8 0
3 years ago
If it takes you 10 seconds to increase from 0 km/h to 50 km/h, what is your acceleration?
ZanzabumX [31]
Acceleration is change in velocity over change in time. Your Δv is +13.9, since you increased speed by 50 km/h which is 13.9 m/s, and your Δt is 10s. 13.9/10 = 1.39 m/s^2, the standard units for acceleration. Make sense?
4 0
3 years ago
Read 2 more answers
Which statements best characterize conductors? Check all that apply.
romanna [79]
It would be the first one and the third one
5 0
3 years ago
Read 2 more answers
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