Answer:
a. 8p
Explanation:
We are given that
Radius of hollow sphere , R1=R
Density of hollow sphere=
After compress
Radius of hollow sphere, R2=R/2
We have to find density of the compressed sphere.
We know that


Therefore,
Volume of sphere=
Using the formula



Hence, the density of the compressed sphere=
Option a is correct.
The heat capacity of the silver spoon at the given temperature difference is 817.65 J.
<h3>
Heat capacity of the silver spoon</h3>
The heat capacity of theb silver spoon is the quantity of heat absorbed by the silver spoon. The heat capacity of the silver spoon at the given temperature difference is calculated as follows;
Q = mcΔθ
where;
- m is mass of the spoon
- c is specific heat capacity of silver = 0.237 J/g⁰C
- Δθ is change in temperature
Q = 50 x 0.237 x (89 - 20)
Q = 817.65 J
Thus, the heat capacity of the silver spoon at the given temperature difference is 817.65 J.
Learn more about heat capacity here: brainly.com/question/16559442
Answer:
Part a)
Average EMF for half cycle is

Part b)
For one complete cycle we will have

Part c)
Maximum induced EMF will be at
t = 0.025 s and 0.075 s
minimum induced EMF is at
t = 0.05s and 0.1 s
Explanation:
As we know that magnetic field is oscillating in direction as well as magnitude
so induced EMF is given as

Part a)
For average value of EMF from positive maximum to negative maximum which is equal to half cycle
so we have




Part b)
For one complete cycle we will have


Part c)
Maximum induced EMF will be at

here we know

t = 0.025 s and 0.075 s
minimum induced EMF is at

so it is
t = 0.05s and 0.1 s
Acceleration is change in velocity over change in time. Your Δv is +13.9, since you increased speed by 50 km/h which is 13.9 m/s, and your Δt is 10s. 13.9/10 = 1.39 m/s^2, the standard units for acceleration. Make sense?
It would be the first one and the third one