Ignore what is scribbled out but I hope this helps!
0, 1, 1, 2, 2, 2, 2, 3, 3, 5
minimum: 0
maximum: 5
mean: 2.1
median: 2
mode: 2
I think the data have zero skew. Its mean, median, and mode are based on 2. It shows symmetry.
Answer:
Actually it's not polygon. it's a nonagon. With r=8.65mm″, the law of cosines gives us side a:
a=√{b²+c²−2bc×cos40°}
a=√{149.645−149.645cos40°}
Area Nonagon = (9/4)a²cos40°
=9/4[149.645−149.645cos40°]cot20°
=336.70125[1−cos(40°)]cot(20°)
Applying an identity for the cos(40°) does not get us very far…
= 336.70125[1−(cos2(20°)−1)]cot(20°)
= 336.70125[2−cos2(20°)]cot(20°)
= 336.70125[2−(1−sin2(20°))]cot(20°)
= 336.70125[1+sin2(20°)]cos(20°)sin(20°)
= 336.70125[cot(20°)+sin(20°)cos(20°)]mm²
Answer:
1920
Step-by-step explanation:
The volume of the rectangle is 1920.
Set two contains an outlier, which is 100
The measure of spread that was most impacted by the outlier is the range
This is because in set two, the median,both quartile and the interquartile range are all closely grouped together but the range is 93, which is far far away from any of those other values
