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andrew-mc [135]
3 years ago
13

write a word problem that can be solved using multiplication of two-digit numbers.Solve your word problem explain the solution.

Mathematics
2 answers:
Mashutka [201]3 years ago
8 0
It should be 420 cause 35 times 12 is 420
andrew11 [14]3 years ago
4 0
____ was planning a birthday party. He/she is planning on inviting 14 people to the party. Each person will be given a goodie-bag at the end of the party. ____ decided that he/she will put 19 gummy worms into each bag. how many gummy worms will ____ need?

The answer to this problem is 266 because 14x19= 266.

the person needs 266 gummy worms if they want to put 19 into each person's goodie-bag
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Find the exact value of the expression.<br> tan( sin−1 (2/3)− cos−1(1/7))
Sonja [21]

Answer:

\tan(a-b)=\frac{2\sqrt{5}-20\sqrt{3}}{5+8\sqrt{15}}

Step-by-step explanation:

I'm going to use the following identity to help with the difference inside the tangent function there:

\tan(a-b)=\frac{\tan(a)-\tan(b)}{1+\tan(a)\tan(b)}

Let a=\sin^{-1}(\frac{2}{3}).

With some restriction on a this means:

\sin(a)=\frac{2}{3}

We need to find \tan(a).

\sin^2(a)+\cos^2(a)=1 is a Pythagorean Identity I will use to find the cosine value and then I will use that the tangent function is the ratio of sine to cosine.

(\frac{2}{3})^2+\cos^2(a)=1

\frac{4}{9}+\cos^2(a)=1

Subtract 4/9 on both sides:

\cos^2(a)=\frac{5}{9}

Take the square root of both sides:

\cos(a)=\pm \sqrt{\frac{5}{9}}

\cos(a)=\pm \frac{\sqrt{5}}{3}

The cosine value is positive because a is a number between -\frac{\pi}{2} and \frac{\pi}{2} because that is the restriction on sine inverse.

So we have \cos(a)=\frac{\sqrt{5}}{3}.

This means that \tan(a)=\frac{\frac{2}{3}}{\frac{\sqrt{5}}{3}}.

Multiplying numerator and denominator by 3 gives us:

\tan(a)=\frac{2}{\sqrt{5}}

Rationalizing the denominator by multiplying top and bottom by square root of 5 gives us:

\tan(a)=\frac{2\sqrt{5}}{5}

Let's continue on to letting b=\cos^{-1}(\frac{1}{7}).

Let's go ahead and say what the restrictions on b are.

b is a number in between 0 and \pi.

So anyways b=\cos^{-1}(\frac{1}{7}) implies \cos(b)=\frac{1}{7}.

Let's use the Pythagorean Identity again I mentioned from before to find the sine value of b.

\cos^2(b)+\sin^2(b)=1

(\frac{1}{7})^2+\sin^2(b)=1

\frac{1}{49}+\sin^2(b)=1

Subtract 1/49 on both sides:

\sin^2(b)=\frac{48}{49}

Take the square root of both sides:

\sin(b)=\pm \sqrt{\frac{48}{49}

\sin(b)=\pm \frac{\sqrt{48}}{7}

\sin(b)=\pm \frac{\sqrt{16}\sqrt{3}}{7}

\sin(b)=\pm \frac{4\sqrt{3}}{7}

So since b is a number between 0 and \pi, then sine of this value is positive.

This implies:

\sin(b)=\frac{4\sqrt{3}}{7}

So \tan(b)=\frac{\sin(b)}{\cos(b)}=\frac{\frac{4\sqrt{3}}{7}}{\frac{1}{7}}.

Multiplying both top and bottom by 7 gives:

\frac{4\sqrt{3}}{1}= 4\sqrt{3}.

Let's put everything back into the first mentioned identity.

\tan(a-b)=\frac{\tan(a)-\tan(b)}{1+\tan(a)\tan(b)}

\tan(a-b)=\frac{\frac{2\sqrt{5}}{5}-4\sqrt{3}}{1+\frac{2\sqrt{5}}{5}\cdot 4\sqrt{3}}

Let's clear the mini-fractions by multiply top and bottom by the least common multiple of the denominators of these mini-fractions. That is, we are multiplying top and bottom by 5:

\tan(a-b)=\frac{2 \sqrt{5}-20\sqrt{3}}{5+2\sqrt{5}\cdot 4\sqrt{3}}

\tan(a-b)=\frac{2\sqrt{5}-20\sqrt{3}}{5+8\sqrt{15}}

4 0
3 years ago
Translations and transformations mastery test
Angelina_Jolie [31]

Answer:

so ....where is the question?

3 0
3 years ago
Read 2 more answers
Please help, I’m not sure what the answer is.
Karo-lina-s [1.5K]

Answer:

The answer is 'C'

Step-by-step explanation:

Congruent simply means "the same." When a line divides two parralel lines transversals are created. This means that there are angles on both lines that are similar. To fully understand which angles would be the same, I reccommend researching "transversals" for more information, or asking your teacher about it as it is hard to explain without a proper diagram.

5 0
3 years ago
HELP ME PLS ! 20 POINTS
anygoal [31]

Answer:

<h3>600 times</h3>

Explain Your Answer:

<h3>50ft x 12in = 600 times</h3>
7 0
2 years ago
Read 2 more answers
Trina, James, and Michael are training for a 10-kilometer race. After 30 minutes of a training run, Michael lead the group, and
Llana [10]

Answer:

1/3

Step-by-step explanation:

1/2 James' fraction of Michael

2/3 Trina's fraction of James

1/2 x 2/3 = 1/3

5 0
3 years ago
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