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Yuliya22 [10]
3 years ago
5

Forces are _______ which means they need to be determined by not only their numeric value (amount of force in Newton's) but also

their _______.
please help this is a science question
Physics
1 answer:
olya-2409 [2.1K]3 years ago
3 0

Forces are <em>vectors</em>, which means they need to be determined by not only their numeric value (amount of force in Newton's) but also their <em>direction</em>.

Some other examples of vector quantities include displacement, acceleration,  velocity, and momentum.  Each of these isn't complete until you know its size and direction.

There are other quantities that have size but <u><em>no</em></u> direction.  They include distance, speed, volume, temperature, cost, and loudness.  These are called "scalars".

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What is the symbol F g mean
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Answer:

Disambiguation

Explanation:

Fg is an abbreviation used in physics to describe the amount of force exerted by gravity on an object, normally represented in units such as the newton.

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The defense is the team that is trying to score a goal.<br> A. True<br> B. False
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Answer:

true

Explanation:

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A 21.6−g sample of an alloy at 93.00°C is placed into 50.0 g of water at 22.00°C in an insulated coffee-cup calorimeter with a h
IrinaK [193]

Answer : The specific heat capacity of the alloy 1.422J/g^oC

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

C_1 = specific heat of alloy = ?

C_2 = specific heat of water = 4.18J/g^oC

m_1 = mass of alloy = 21.6 g

m_2 = mass of water = 50.0 g

T_f = final temperature of system = 31.10^oC

T_1 = initial temperature of alloy = 93.00^oC

T_2 = initial temperature of water = 22.00^oC

Now put all the given values in the above formula, we get

21.6g\times c_1\times (31.10-93.00)^oC=-50.0g\times 4.18J/g^oC\times (31.10-22.00)^oC

c_1=1.422J/g^oC

Therefore, the specific heat capacity of the alloy 1.422J/g^oC

6 0
2 years ago
What magnitude charge creates a 1.0 n/c electric field at a point 1.0 m away?
Stolb23 [73]

Answer:

1.1\cdot 10^{-10}C

Explanation:

The electric field produced by a single point charge is given by:

E=k\frac{q}{r^2}

where

k is the Coulomb's constant

q is the charge

r is the distance from the charge

In this problem, we have

E = 1.0 N/C (magnitude of the electric field)

r = 1.0 m (distance from the charge)

Solving the equation for q, we find the charge:

q=\frac{Er^2}{k}=\frac{(1.0 N/c)(1.0 m)^2}{9\cdot 10^9 Nm^2c^{-2}}=1.1\cdot 10^{-10}C

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