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miss Akunina [59]
3 years ago
15

If the time of impact in a collision is extended by 3 times, by hour much is

Physics
1 answer:
vodomira [7]3 years ago
4 0

Answer:

The force of the impact would be smaller

Explanation:                                                          Examples:

If the force is big then the time would be small (2500N of Force = 10 seconds)

If the force is small then the time would be big (250N of Force = 50 seconds)

Impulse/Collision -> [Ft] = [M (vf-vo)] <- Change in momentum

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Read 2 more answers
Q1) An aeroplane covers a certain distance at a speed of 240 kmph in 5 hours.To cover the same distance in 1(2/3) hours, it must
Pepsi [2]

Answer:

D) 720 kmph

Explanation:

First, let's find what distance this aeroplane covered. Distance (d) is the product of speed and time - here, we have a speed of 240 kmph and a time of 5 hours, gives us

d=240\cdot5=1200 km

Using that same fact, we can set up a new equation to solve for speed (s) when we have a distance of 1200 km and a time of 1 2/3 hours. For the sake of cleanliness, I'm gonna rewrite 1 2/3 as the improper fraction 5/3:

1200=(5/3)s

Multiplying both sides of the equation by 3/5:

s=(3/5)(1200)=720 kmph

So our answer is D.

8 0
3 years ago
To find some of the parameters characterizing an object moving in a circular orbit.The motivation for Isaac Newton to discover h
tamaranim1 [39]

Answer:

K = \frac{GMm}{2r}

T^2 = 4\pi^2(\frac{r^3}{GM})

Explanation:

As we know that for a satellite the force of gravitation is equal to the centripetal force

so we will have

F = \frac{GMm}{r^2}

\frac{mv^2}{r} = \frac{GMm}{r^2}

so we know that kinetic energy is given as

K = \frac{1}{2}mv^2

so we have

K = \frac{GMm}{2r}

now for time period we know

T = \frac{2\pi r}{v}

from above expression of kinetic energy we have

v = \sqrt{\frac{GM}{r}}

so we have

T = \frac{2\pi r}{\sqrt{\frac{GM}{r}}}

so square of time period is given as

T^2 = 4\pi^2(\frac{r^3}{GM})

3 0
3 years ago
2 masses of 4kg and 2.5kg have a separation of r =1.5m. Calculate the force of gravitational attraction between them (take g as
Evgesh-ka [11]

Answer:

F = 29.64 × 10-¹¹N

Explanation:

From newton's law of gravitation which states that every object in the universe will attract each other with a force which is directly proportional to the product of their masses and inversely proportional to the square of their distance apart.

That is,   F = (Gm1m2)/ r²

From the question m1=4kg, m2 = 2.5kg, r= 1.5m,G = 6.67×10-¹¹

F=( 6.67×10-¹¹ × 4 × 2.5) / 1.5²

F = (66.7×10-¹¹) / 2.25

F = 66.7/2.25 × 10-¹¹ N

F = 29.64 × 10-¹¹N

F = 29.64 × 10-¹¹N

I hope this was helpful, please mark as brainliest

5 0
3 years ago
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