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Alik [6]
3 years ago
7

a water-balloon launcher with mass 4 kg fires a 0.5 kg balloon with a velocity of 3 m/s to the east. what is the recoil velocity

of the launcher?
Physics
2 answers:
kotykmax [81]3 years ago
5 0
I think we will use the law of conservation of linear momentum;
M1V1 = M2V2
M1 =  4 kg (mass of the water balloon launcher)
V1=?
M2= 0.5 kg ( mass of the balloon)
V2 = 3 m/s

Therefore; 4 V1 = 0.5 × 3
                   4V1= 1.5
                     V1= 1.5/4
                          = 0.375 m/s










Masteriza [31]3 years ago
5 0

Answer:

0.38 m/s west, for all a p e x users

Explanation:

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Block 1 (mass 2.00 kg) is moving rightward at 10.0 m/s and block 2 (mass 5.00 kg) is moving rightward at 3.00 m/s. The surface i
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Answer:

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Now applying the principle of energy conservation:

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5 0
2 years ago
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beks73 [17]

Answer:

Acceleration is 0.25m/s^2

Explanation:

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Therefore,

a = v^2 / r

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2 years ago
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beks73 [17]
No idea man good luck though
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3 years ago
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