A wave with a period of 1⁄3 second has a frequency of D. 3 Hz. To
calculate this we will use the formula that represents the correlation
between a frequency (f) and a time period (T): T = 1/f. Or: f = 1/T. The
unit for the time period is second "s" while the unit for frequency is
Hertz "Hz" (=1/s). We know that T = 1/3 s. That means that f = 1/(1/3s) =
3 1/s = 3 Hz.
Answer:
θ=5.65°
Explanation:
Given Data
Mass m=1.5 kg
Length L=0.80 m
First spring constant k₁=35 N/m
Second spring constant k₂=56 N/m
To find
Angle θ
Solution
As the both springs take half load so apply Hooks Law:
Force= Spring Constant ×Spring stretch
F=kx
x=F/k
as
![d=x_{1}-x_{2}\\ as \\x=F/k\\so\\d=\frac{F_{1} }{k_{1}} -\frac{F_{2}}{k_{2}}\\ Where \\F=1/2mg\\d=\frac{(1/2)mg}{k_{1}} -\frac{(1/2)mg}{k_{2}}\\ d=\frac{mg}{2}(\frac{1}{k_{1}} -\frac{1}{k_{2}} )\\ And\\Sin\alpha=d/L\\\\alpha =sin^{-1}[\frac{mg}{2L}(1/k_{1}-1/k_{2})]\\\alpha =sin^{-1}[\frac{(1.5kg)(9.8m/s^{2} )}{2(0.80m)}(1/35Nm-1/56Nm) ]\\\alpha =5.65^{o}](https://tex.z-dn.net/?f=d%3Dx_%7B1%7D-x_%7B2%7D%5C%5C%20%20as%20%5C%5Cx%3DF%2Fk%5C%5Cso%5C%5Cd%3D%5Cfrac%7BF_%7B1%7D%20%7D%7Bk_%7B1%7D%7D%20-%5Cfrac%7BF_%7B2%7D%7D%7Bk_%7B2%7D%7D%5C%5C%20Where%20%5C%5CF%3D1%2F2mg%5C%5Cd%3D%5Cfrac%7B%281%2F2%29mg%7D%7Bk_%7B1%7D%7D%20-%5Cfrac%7B%281%2F2%29mg%7D%7Bk_%7B2%7D%7D%5C%5C%20d%3D%5Cfrac%7Bmg%7D%7B2%7D%28%5Cfrac%7B1%7D%7Bk_%7B1%7D%7D%20-%5Cfrac%7B1%7D%7Bk_%7B2%7D%7D%20%29%5C%5C%20And%5C%5CSin%5Calpha%3Dd%2FL%5C%5C%5C%5Calpha%20%3Dsin%5E%7B-1%7D%5B%5Cfrac%7Bmg%7D%7B2L%7D%281%2Fk_%7B1%7D-1%2Fk_%7B2%7D%29%5D%5C%5C%5Calpha%20%20%20%3Dsin%5E%7B-1%7D%5B%5Cfrac%7B%281.5kg%29%289.8m%2Fs%5E%7B2%7D%20%29%7D%7B2%280.80m%29%7D%281%2F35Nm-1%2F56Nm%29%20%5D%5C%5C%5Calpha%20%3D5.65%5E%7Bo%7D)
θ=5.65°
Answer:
The particles have just enough energy to move past each other.
Answer:
12.0 Volt
Explanation:
Step 1: Given data
Resistance of the ohmic dipole (R): 100 Ohm
Intensity of current (I): 120 mA (0.120 A)
Step 2: Calculate the voltage (V) across this chemical dipole
To calculate the voltage across the ohmic dipole, we will use Ohm's law.
I = V/R
V = I × R
V = 0.120 A × 100 Ohm = 12.0 V
The book Two New Sciences is the book that would later influence Sir Isaac Newton
