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4 years ago

Does this graph show a function explain how you know

Mathematics

2 answers:

Wewaii [24]4 years ago

8 0

C. No, the graph fails the vertical line test. I believe that is the answer.

fredd [130]4 years ago

6 0

Answer:

Option (C) is correct.

Step-by-step explanation:

A function f : A -> B means every element of A is mapped to a unique element of B, where A and B are non-empty sets.

Now, to check whether a graph is a function or not, there is a test called 'Vertical Line Test'.

In the test, we draw a vertical line passing through the graph. Then:

1. If the line cuts exactly at one point of the graph, then the given graph is a function.

2. If the graph cuts at more than one points, then the graph is not a function as it does not satisfy the definition a function.

Now, in the given graph, if you draw a vertical line on the right side of origin, it will cut at more than one point.

Hence, the graph fails the vertical line test and it is not a function.

So, option (C) is correct.

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Help!!!! What is the answer??????

ANTONII [103]

Answer:I think is A

Step-by-step explanation:

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3 years ago

If P and Q are two sets then n( P-Q) means ?

Lapatulllka [165]

$\huge{\mathbb{ \tt{ANSWER}}}$

I shall use the symbol U for union

^ for intersection

~ for complement

The property of set subtraction states that for any sets X and Y, X-Y = X ^ Y~

That is in words, X throw away Y is the same as the intersection of X and the complement of Y

or X and anything NOT in Y

At the SET level, the proof looks like this:

(P-Q) U (Q-P) = « given

(P^Q~) U (Q ^ P~) = « property of set subtraction

(P U Q) ^ (P U P~) ^ (Q~ U Q) ^ (Q~ U P~) = « distributive property

(P u Q) ^ (Q~ U P~) = « Union of any set with it's complement is the universal

set which gets dropped by any intersection of a non-universal set

(P u Q ) ^ (Q ^ P)~ = « De Morgan's Law

(P u Q) - (Q ^ P) = « property of set subtraction

(P u Q) - (P ^ Q) « commutative property

At the ELEMENT level, the proof looks like this:

» Proves left side is subset of right side

If x is in (P-Q) U (Q-P) then x is in (P-Q) OR x is in (Q-P)

If x is in P-Q then x is in P but not in Q.

Then X is in P U Q.

Since x is not in Q, x is NOT in P ^ Q

Hence x is in P U Q but NOT in P^Q, which

means it is an element if (P U Q) - (P ^ Q)

Therefore x is an element of the set defined by the right side, which means (P-Q) U (Q-P) is a subset of (P U Q) - (P ^ Q)

« proves right side is subset of the left side

If x is an element of (P U Q) - (P ^ Q) then

x is in (P U Q) but NOT in (P^Q)

Since x is in P U Q, x is in P OR x is in Q.

Since x is NOT in (P^Q) then x is NOT in BOTH P and Q.

Hence x is in either P or Q but not both.

If x is in P, then x is not in Q, so x is in P-Q.

Therefore x is in (P-Q) U (Q-P).if x is in Q, then x is not in P, so x is in Q-P.Therefore x is in (Q-P) U (P-Q).There x is an element of set defined by the left side, which menas (P u Q)-(P ^Q) is a subset of (P-Q) U (Q-P).

#CarryOnLearning

#LetsEnjoyTheSummer

8 0

3 years ago

A bag contains blue marbles and red marbles, 58 in total. The number of blue marbles is 4 more than 5 times the number of red ma

tatiyna

Answer:

49 blue marbles

Step-by-step explanation:

From the question we are given;

Total number of marbles = 58
Blue marbles are 4 more than 5 times the red marbles

We need to determine the number of blue marbles;

Assuming the number of red marbles is x

Then, blue marbles will be 5x + 4

Therefore;

x + 5x + 4 = 58

6x + 4 = 58

6x = 54

x = 9

5x + 4 = 5(9) + 4 = 49

Therefore, the red marbles are 9 while the blue marbles are 49

Hence there are 49 blue marbles

3 0

3 years ago

I NEED HELP ASAPPP! PLEASEEE

Andre45 [30]

Answer:

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Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Number that is greater than 150 and divisible by 19

Nikolay [14]

One possible answer is 171 ÷ 19 = 9

7 0

3 years ago