Answer:
Mohamed Osama El Sayed El kordy
PCl₅ reacts upon contact with water to launch hydrogen chloride and supply phosphorus oxides. the primary hydrolysis product is phosphorus oxychloride PCl₅ + H₂O ========> POCl₃ + 2HCl.
Phosphorus trichloride appears as a colorless or slightly yellow fuming liquid with a pungent and irritating odor resembling that of hydrochloric acid. Causes severe burns to skin, eyes and mucous membranes.
Divide the mass of the material through its molar mass. The molar mass of a substance is the mass in grams of 1 mole of that substance. This mass is given via the atomic weight of the chemical unit that makes up that substance in atomic mass units.
One mole is described as the amount of substance containing as many number one entities atoms, molecules, ions, electrons, radicals, and lots of others. As there are atoms in 12 grams of carbon - 12(6. 023×10²³. The mass of one mole of a substance equals to its relative molecular mass expressed in grams.
Learn more about phosphorous trichloride here:-brainly.com/question/2626850
#SPJ4
In oil and gas industry:
When crude oil get extracted from well, salt water and some other stuff needs to be removed before oil can be sued in the car
Answer:
Explanation:
First, we must find the density of the unknown metal.
Density is found by dividing the mass by the volume.
The mass of the metal is 89 grams and the density is 10 cubic centimeters.
Substitute the values into the formula.
Divide.
Now we know the density and can identify the unknown metal.
- Nickel: 8.9 g/cm³
- Silver: 10.5 g/cm³
- Lead: 11.35 g/cm³
- Mercury: 13.55 g/cm³
The density matches nickel's density. Therefore, this metal must be <u>nickel.</u>
Answer:
Option D. AlCl₃, MgC₂
Explanation:
We need to dissociate all the salts, to determine the i. (Van't Hoff factor).
The salt who has the highest value, will be the better conductor of electricity
CsCl → Cs⁺ + Cl⁻ i = 2
CaCl → Ca²⁺ + Cl⁻ i = 2
CaS → Ca²⁺ + S⁻² i = 2
Li₂S → 2Li⁺ + S⁻² i = 3
KBr → K⁺ + Br⁻ i = 2
AlCl₃ → Al³⁺ + 3Cl⁻ i = 4
MgC₂ → Mg²⁺ + 2C⁻ i = 3
KI → K⁺ + I⁻ i = 2
K₂S → 2K⁺ + S⁻² i = 3
The biggest i, is in pair D.