Answer:
NO.3) Mass of Al2O3 formed = 229.5g
Answer:
P(total) = 1329 torr
Explanation:
Given data:
Pressure of nitrogen = 984 torr
Pressure of carbon dioxide = 345 torr
Total pressure of system = ?
Solution:
The given problem will be solve through the Dalton law of partial pressure of gases.
According to the this law,
The total pressure exerted by the mixture of gases is equal to the sum of partial pressure of individual gas.
Mathematical expression,
P(total) = P₁ + P₂ +.......+ Pₙ
Here we will put the values in formula,
P₁ = partial pressure of nitrogen
P₂ = partial pressure of carbon dioxide
P(total) = 984 torr + 345 torr
P(total) = 1329 torr
First calculate the moles of N2 and H2 reacted.
moles N2 = 27.7 g / (28 g/mol) = 0.9893 mol
moles H2 = 4.45 g / (2 g/mol) = 2.225 mol
We can see that N2 is the limiting reactant, therefore we
base our calculation from that.
Calculating for mass of N2H4 formed:
mass N2H4 = 0.9893 mol N2 * (1 mole N2H4 / 1 mole N2) * 32
g / mol * 0.775
<span>mass N2H4 = 24.53 grams</span>
Answer: The partial pressure of Argon , Neon and krypton are 48 kPa , 24 kPa and 8 kPa respectively.
Explanation:
According to Raoult's Law , the partial pressure of each component in the solution is equal to the total pressure multiplied by its mole fraction. It is mathematically expressed as
where, 
= partial pressure of component A
= mole fraction of A
= total pressure
mole fraction of Ar = 
mole fraction of Ne = 
mole fraction of Kr = 
