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torisob [31]
3 years ago
11

Molecular formula for C4H10

Chemistry
1 answer:
Gnesinka [82]3 years ago
6 0
I think this is what you mean:

    H H H H
H-C-C-C-C-H
    H H H H

OR 

<span>CH3CH2CH2CH3
</span>
If not, clarify and I will be happy to help.
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combustion analysis of an unknown compound provides the following data: 73.5 grams carbon (C), 4.20 grams hydrogen (H) and 72.3
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M(C)=73.5 g
m(H)=4.20 g
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mass of compound
m=m(C)+m(H)+m(Cl)

m=73.5+4.20+72.3=150 g

w(H)=100m(H)/m
w(H)=100*4.20/150=2.8%

w(Cl)=100m(Cl)/m
w(Cl)=100*72.3/150=48.2%

w(C)=100-w(H)-w(Cl)
w(C)=100-2.8-48.2=49.0%
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