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eduard
1 year ago
11

When reacted with elemental chlorine at room temperature, liquid phosphorous trichloride (PCl3) is converted to solid phosphorou

s pentachloride (PCl5).
Chemistry
1 answer:
Sergeu [11.5K]1 year ago
6 0

PCl₅ reacts upon contact with water to launch hydrogen chloride and supply phosphorus oxides. the primary hydrolysis product is phosphorus oxychloride     PCl₅ + H₂O ========>  POCl₃ + 2HCl.

Phosphorus trichloride appears as a colorless or slightly yellow fuming liquid with a pungent and irritating odor resembling that of hydrochloric acid. Causes severe burns to skin, eyes and mucous membranes.

Divide the mass of the material through its molar mass. The molar mass of a substance is the mass in grams of 1 mole of that substance. This mass is given via the atomic weight of the chemical unit that makes up that substance in atomic mass units.

One mole is described as the amount of substance containing as many number one entities atoms, molecules, ions, electrons, radicals, and lots of others. As there are atoms in 12 grams of carbon - 12(6. 023×10²³. The mass of one mole of a substance equals to its relative molecular mass expressed in grams.

Learn more about  phosphorous trichloride here:-brainly.com/question/2626850

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Answer:

neutralization reaction! Aka: option C!

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Explanation:

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Metallic bonds form between what kinds of atoms?
valentinak56 [21]

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Many double-displacement reactions are enzyme-catalyzed via the "ping pong" mechanism, so called because the reactants appear to
zhenek [66]

Answer:

<u>D. It will decrease by a factor of 4</u>

Explanation:

According to the question , the equation follows :

A+B\rightarrow C+D

Rate law : This states the rate of reaction is directly proportional to concentration of reactants with each reactant raised to some power which may or may not be equal to the stoichiometeric coefficient.

Rate\ \alpha [A]^{a}[B]^{b}

r=[A]^{a}[B]^{b}.................(1)

STEP": First, find out the power "a" and "b"

a+b = 3 (because it is given that the reaction follow 3rd order-kinetics)

According to question, <u><em>doubling the concentration of the first reactant causes the rate to increase by a factor of 2 means,</em></u>

r' = 2r if [A'] = 2[A]

Here [B] is uneffected means [B']=[B]

hence new rate =

r'=[A']^{a}[B']^{b}

Put the value of [A'] , [B'] and r' in the above equation:

2r=[2A]^{a}[B]^{b}...........(2)

Divide equation (1) by (2) we , get

\frac{2r}{r}=\frac{[2A]^{2}[B]^{b}}{[A]^{a}[B]^{b}}

2= 2(\frac{A}{A})^{a}\times (\frac{B}{B})^{b}

Here A and A cancel each other

B and B cancel each other

We get,

2= 2^{a}\times 1^{b}

1^b = 1 ( power of 1 = 1)

2= 2^{a}

This is possible only when a = 1

We know that : a + b = 3

1 + b = 3

b =3 -1  = 2

b = 2

Hence the rate law becomes :

r=[A]^{a}[B]^{b}

<u>r=[A]^{1}[B]^{2}.............(3)</u>

Look in the question now, it is asked to calculate the concentration of [B],if  cut in half

Hence

[B']=1/2[B]

Insert the value of [B'] in equation (3)

r'=[A]^{1}[B']^{2}

r'=[A]^{1}(\frac{1}{2}[B])^{2}

r'=\frac{1}{4}[A]^{1}[B]^{2}............(a)

But

r=[A]^{a}[B]^{b}..............(b)

Compare equation (a) and (b) , we get

new rate r' =

<u>r' = 1/4 r</u>

7 0
3 years ago
What mass of water is produced from the complete combustion of 4.80×10−3 g of methane?
AnnZ [28]

Answer:Mass of H20 = 0.0108g

Explanation:

The explanation is attached.

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3 years ago
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