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fenix001 [56]
3 years ago
11

How many grams of iron, Fe, are reacted to form 16.0 grams of FeS (87.91 g/mol)

Chemistry
2 answers:
Pavlova-9 [17]3 years ago
8 0

Answer is: 10.164 grams of iron.

Balanced chemical reaction: 8Fe + S₈ → 8FeS.

m(FeS) = 16.0 g; mass of the compound.

M(FeS) = 87.91 g/mol; molar mass of the compound.

n(FeS) = m(FeS) ÷ M(FeS).

n(FeS) = 16 g ÷ 87.91 g/mol.

n(FeS) = 0.182 mol; amount of substance.

From chemical reaction: n(FeS) : n(Fe) = 8 : 8 (1 : 1).

n(Fe) = 0.182 mol.

m(Fe) = n(Fe) · M(Fe).

m(Fe) = 0.182 mol · 55.845 g/mol.

m(Fe) = 10.164 g.

shtirl [24]3 years ago
4 0

the complete question and answer in the attached figure


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Pb(NO3)2(aq) + KCl(aq) ---- → KNO3(aq) + PbC12(s)
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What is the molarity of a stock solution if 60 mL were used to make 150 mL of a .5M solution
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The answer to your question is 1.25 M

Explanation:

Data

Molarity 1 = ?

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Volume 2 = 150 ml

Process

1.- Write the dilution formula

       Molarity 1 x Volume 1 = Molarity 2 x Volume 2

-Solve for Molarity 1

       Molarity 1 = Molarity 2 x Volume 2 / Volume 1

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3 years ago
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