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Viefleur [7K]
3 years ago
9

What is 3200000 in scientific notation?

Chemistry
2 answers:
Julli [10]3 years ago
6 0
3.2 times 106 is what I got :)
BabaBlast [244]3 years ago
3 0
This would be 32^5. The little 5 shows you how many zeros you need to add.
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A rigid vessel contains 3.98 kg of refrigerant-134a at 700 kPa and 60°C. Determine the volume of the vessel and the total intern
Arada [10]

<u>Answer:</u> The volume of the vessel is 0.1542m^3 and total internal energy is 162.0 kJ.

<u>Explanation:</u>

  • To calculate the volume of water, we use the equation given by ideal gas, which is:

PV=nRT

or,

PV=\frac{m}{M}RT

where,

P = pressure of container = 700 kPa

V = volume of container = ? L

m = Given mass of R-134a = 3.98 kg = 3980 g    (Conversion factor: 1kg = 1000 g)

M = Molar mass of R-134a = 102.03 g/mol

R = Gas constant = 8.31\text{L kPa }mol^{-1}K^{-1}

T = temperature of container = 60^oC=[60+273]K=333K

Putting values in above equation, we get:

700kPa\times V=\frac{3980g}{102.03g/mol}\times 8.31\text{L kPa }\times 333K\\\\V=154.21L

Converting this value into m^3, we use the conversion factor:

1m^3=1000L

So, \Rightarrow (\frac{1m^3}{1000L})\times 154.21L

\Rightarrow 0.1542m^3

  • To calculate the internal energy, we use the equation:

U=\frac{3}{2}nRT

or,

U=\frac{3}{2}\frac{m}{M}RT

where,

U = total internal energy

m = given mass of R-134a = 3.98 kg = 3980 g  (Conversion factor: 1kg = 1000g)

M = molar mass of R-134a = 102.03 g/mol

R = Gas constant = 8.314J/K.mol

T = temperature = 60^oC=[60+273]K=333K

Putting values in above equation, we get:

U=\frac{3}{2}\times \frac{3980g}{102.03g/mol}\times 8.314J/K.mol\times 333K\\\\U=161994.6J

Converting this into kilo joules, we use the conversion factor:

1 kJ = 1000 J

So, 161994.6 J = 162.0 kJ

Hence, the volume of the vessel is 0.1542m^3 and total internal energy is 162.0 kJ.

6 0
3 years ago
Which of the following is an organic compound
mel-nik [20]
An Organic Compound is when Hydrogen and Nitrogen are bonded.

Therefore A is the answer
6 0
3 years ago
Read 2 more answers
Difference between elimination and substitution​
kotegsom [21]

Answer:

The obvious difference between substitution and elimination reactions is that substitution reactions replace one substituent with another while elimination reactions simply remove the substituent. ... The major difference between the groups is the number of steps the reaction takes place over.

substitution and elimination can be seenis by looking at the bond or the H+ . When substitution occurs, the H+ will be subtituted with other atom. As for elimination, when this reaction occur which mostly involve alkane, new bondwill appear.

Thank you and please rate me as brainliest as it will help me to level up

5 0
3 years ago
Convert 3.00 * 10 ^ 26 molecules of carbon dioxide gas at STP to L.
Bond [772]

Answer: 1. The coefficient is 1.12

2. The exponent is 4

3. There are 3 significant digits

4. The rightmost significant figure is 2.

Explanation:

Scientific notation is defined as the representation of expressing the numbers that are too big or too small and are represented in the decimal form with one digit before the decimal point times 10 raise to the power.

For example : 5000 is written as 5.0\times 10^3

According to avogadro's law, 1 mole of every gas contains avogadro's number 6.023\times 10^{23} of particles and occupy 22.4 L at STP.

6.023\times 10^{23} molecules of CO_2 occupy = 22.4 L at STP.

Thus 3.00\times 10^{26} molecules of CO_2 occupy = \frac{22.4}{6.023\times 10^{23}}\times 3.00\times 10^{26}=11.2\times 10^3 L at STP.

Scientific notation = 1.12\times 10^4L

The coefficient is 1.12

The exponent is 4

There are 3 significant digits

The rightmost significant figure is 2.

4 0
2 years ago
Why pH level test is important in lotion testing? Why it matter? Explain your answer
IceJOKER [234]

Answer: The ph value of the skin plays an essential role in protecting the skin.

Explanation:

An acidic protective layer is crucial for the functioning of the skin's protective barrier. Neutralizes aggressive alkaline substances (eg, aggressive surfactants), inhibits bacterial growth and restores and maintains an optimal acidic environment in which natural flora can develop.

If there is a rise in the ph value of the skin, the nature of the skin may become disturbed. Essential epidermal lipids can no longer be synthesized, so in this case, the skin loses and dries. By breaking its protective function, the skin can become dry, sensitive, or extremely

3 0
3 years ago
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