Heat required = Q = 40 kcal
<h3>Further explanation</h3>
Given
mass of 500 g ice
Required
Heat required
Solution
The heat to change the phase can be formulated :
- Q = m.Lf (melting/freezing)
- Q = m.Lv (vaporization/condensation)
Lf=latent heat of fusion
Lv=latent heat of vaporization
Lf for water = 334 kj/kg=6.01 kJ/mol = 80 cal/g
Phase change(ice to water)
Q= 500 g x 80 cal/g
Q = 40 kcal
A mol=6.02*10^23
so
distance from earth to moon is 230,100 miles
1 big mac is about 2 inches
1 mile=5280 feet=63360inches
230,100 times 63360=14,579,136,000 inches is distance
6.02 times 10^23 times 2=x times 14,579,136,000
divide both sides by 2
6.02 times 10^23=x times 7,289,568,000
divide both sides by 6.02
10^23=x times 1210891694.35159
divide both sides by 1210891694.35159
825583769024485.8
about 825,583,769,024,486 times
0.0857
Rounding off to three digits
Since 7 is more than five you change it to 0 and add 1 to 5
A: 0.086
Breaking down that’s why they make land slides
Answer: The mass of potassium bromide that must be dissolved in the same mass of X to produce the same depression in freezing point is 58.2 grams
Explanation:
Depression in freezing point is given by:
= Depression in freezing point
i= vant hoff factor = 1 (for non electrolyte)
= freezing point constant =
m= molality = 
Let Mass of solute (KBr) = x g
Thus the mass of potassium bromide that must be dissolved in the same mass of X to produce the same depression in freezing point is 58.2 grams
