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BabaBlast [244]
3 years ago
10

No spam or links! Thanks!

Chemistry
1 answer:
Monica [59]3 years ago
5 0

Answer:

364 K or 91°C

Explanation:

Applying,

V₁/T₁ = V₂/T₂................ Equation 1

Where V₁ = Initial Volume, V₂ = Final volume, T₁ = initial Temperature, T₂ = final Temperature.

make T₂ the subject of the equation,

T₂ = V₂T₁/V₁................. Equation 2

From the question,

Given: V₁ = 375 mL, V₂ = 500 mL, T₁ = 0.0°C = (273+0) K = 273 K

Substitute these values into equation 2

T₂ = (500×273)/375

T₂ = 364 K

T₂ = (364-273) °C = 91 °C

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D. Barometer. Hope this helps
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A small positively charged nucleus surrounded by revolving negatively charged electrons in fixed orbits

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Suppose that you are performing a titration on a monoprotic acid. Titration of this monoprotic acid required a volume of 0.1L of
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Answer: A) More base is likely required to reach the endpoint for the diprotic acid than for the monoprotic acid under these conditions

Explanation:

The monoprotic acid (HA) has a valency of 1 and diprotic acid  (H_2A) has a valency of 2.

As the concentration and volume of the diprotic acid and the monoprotic acids are equal.

The neutralization reaction for monoprotic acid is:

HA+BOH\rightarrow BA+H_2O

The neutralization reaction for diprotic acid is:

H_2A+2BOH\rightarrow B_2A+2H_2O

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6 0
3 years ago
1.
GarryVolchara [31]

Answer:

The value of the Golden Igloo is $227.4 million.

Explanation:

First, we need to find the inner and the outer volume of the half-spherical shell:

V_{i} = \frac{1}{2}*\frac{4}{3}\pi r_{i}^{3}

V_{o} = \frac{1}{2}*\frac{4}{3}\pi r_{o}^{3}

The total volume is given by:

V_{T} = V_{o} - V_{i}

Where:

V_{i}: is the inner volume

r_{i}: is the inner radius = 1.25/2 = 0.625 m

V_{o}: is the outer volume

r_{o}: is the outer radius = 1.45/2 = 0.725 m

Then, the total volume of the Igloo is:

V_{T} = \frac{2}{3}\pi r_{o}^{3} - \frac{2}{3}\pi r_{i}^{3} = \frac{2}{3}\pi [(0.725 m)^{3} - (0.625 m)^{3}] = 0.29 m^{3}

Now, by using the density we can find the mass of the Igloo:

m = 19.3 \frac{g}{cm^{3}}*0.29 m^{3}*\frac{(100 cm)^{3}}{1 m^{3}} = 5.60 \cdot 10^{6} g

Finally, the value (V) of the antiquity is:

V = \frac{\$ 1263}{oz}*5.60 \cdot 10^{6} g*\frac{1 oz}{31.1034768 g} = \$ 227.4 \cdot 10^{6}  

Therefore, the value of the Golden Igloo is $227.4 million.

I hope it helps you!  

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